Lemma 15. If n ∈ N then 0 · n = 0. Lemma 16. If n ∈ N then 1 · n = n. Exercise 28. Prove the above two lemmas using the induction axiom.
Lemma 15. If n ∈ N then 0 · n = 0. Lemma 16. If n ∈ N then 1 · n = n. Exercise 28. Prove the above two lemmas using the induction axiom.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Lemma 15. If n ∈ N then 0 · n = 0.
Lemma 16. If n ∈ N then 1 · n = n.
Exercise 28. Prove the above two lemmas using the induction axiom.
Expert Solution
Lemma 15.
If n ∈ N then 0 · n = 0.
Base case: For n = 1, 0 · 1 = 0,
Induction Hypothesis: Assume that the above result holds true for all positive integers less than or equal to n, then
Inductive step: We have to prove that the result holds true for n:= n + 1,
So now, for n:= n + 1
0 · (n + 1) = 0 · n + 0 · 1 = 0 + 0 = 0 by using Induction Hypothesis and the base case.
Thus, we proved the result for n:= n + 1 which implies that 0 · n = 0 for every n ∈ N by using principle of mathematical induction.
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