Lemma 14.11 Let Sn = integer n. n k=1 = 1+ 1 1 n · + -, where n € N. Then S2 ≥1+ for every positive 2 n

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Please explain the highlighted part of the following proof step by step, It really goes to fast for me on how they suddenly substitute and change variables, please if able really show what is done with each step in detail

 

Lemma 14.11 Let Sn =
integer n.
Proof
n
k=1
= 1+
1
1
n
+-, where ne N. Then S2 ≥1+ for every positive
2
n
We proceed by induction. For n = 1, $₂¹ = 1 + and so the result holds for n = 1.
1
2
k
, where ke N. We show that S₂k+1 ≥ 1+
Assume that s₂k ≥ 1+
that
2
$2k+1 = 1+
1
2
= $₂k +
≥ S₂k +
= S₂k +
+
1
2k + 1
1
2k+1
2k
2k+1
1
2k+1
1
2k +2
1
2k+1
+
+
+
S2k +
k 1
≥1+=+ =1+
2 2
+
1
+
2
k + 1
2
+
1
2k+1
1
ok+1
By the Principle of Mathematical Induction, S2″ ≥1+
integer n.
n
IN
k+1
2
Now observe
for every positive
Transcribed Image Text:Lemma 14.11 Let Sn = integer n. Proof n k=1 = 1+ 1 1 n +-, where ne N. Then S2 ≥1+ for every positive 2 n We proceed by induction. For n = 1, $₂¹ = 1 + and so the result holds for n = 1. 1 2 k , where ke N. We show that S₂k+1 ≥ 1+ Assume that s₂k ≥ 1+ that 2 $2k+1 = 1+ 1 2 = $₂k + ≥ S₂k + = S₂k + + 1 2k + 1 1 2k+1 2k 2k+1 1 2k+1 1 2k +2 1 2k+1 + + + S2k + k 1 ≥1+=+ =1+ 2 2 + 1 + 2 k + 1 2 + 1 2k+1 1 ok+1 By the Principle of Mathematical Induction, S2″ ≥1+ integer n. n IN k+1 2 Now observe for every positive
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