Lec.1 / Solution of first order differential equation / c) Integrating Factor dy sec(x) dx + sec(x)tan(x)y = sec² (x) Ex 1: Solve by IF method d cos(x) dx dy + sin(x)y = 1, at y(t) = 2 dx d (sec(x) y) dx = :(sec(x)y) = sec² (x) Divide by cos(x) | sec? (x)dx dx dy + tan(x)y = sec(x) dx sec(x) у 3D tапx + с 1 • P(x) : y = cos(x) Multiply by cos(x) sin(x) cos(x) tan(x) • IF = = eJ tan(x) dx sin(x) + c cos(x) 1 y = cos(x) y = sin(x) + c. cos(x) if y(n) = 2 2 = sin(n) + c. cos(T) c = -2 y = sin(x) – 2cos(x) • IF = eln sec(x) • IF = eln|sec(x)| • IF = sec(x) 19
Lec.1 / Solution of first order differential equation / c) Integrating Factor dy sec(x) dx + sec(x)tan(x)y = sec² (x) Ex 1: Solve by IF method d cos(x) dx dy + sin(x)y = 1, at y(t) = 2 dx d (sec(x) y) dx = :(sec(x)y) = sec² (x) Divide by cos(x) | sec? (x)dx dx dy + tan(x)y = sec(x) dx sec(x) у 3D tапx + с 1 • P(x) : y = cos(x) Multiply by cos(x) sin(x) cos(x) tan(x) • IF = = eJ tan(x) dx sin(x) + c cos(x) 1 y = cos(x) y = sin(x) + c. cos(x) if y(n) = 2 2 = sin(n) + c. cos(T) c = -2 y = sin(x) – 2cos(x) • IF = eln sec(x) • IF = eln|sec(x)| • IF = sec(x) 19
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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