Least squares approximation is a method for finding the line with minimum vertical distance from a set of points. Let the equation of the best-fit line be y = mx + b, where the slope m and the y-intercept b must be determined using the least squares condition. Assume there are three data points (1,2), (2,3), and (3,5). The following function E(m,b) represents the sums of the squares of the vertical distances of each point from the best-fit line. Find the critical points of E and find the values of m and b that minimize E. Graph the three data points and the best-fit line. E(m,b) = [(m +b) - 2]² + [(2m + b) − 3]² + [(3m + b) - 5]² y (Xn-1' Yn-1) Em (m,b) = Eb (m,b) = (Simplify your answer. Do not factor.) regression line (x₁, y₁) (X₂² Y₂) To find the critical points, it will first be necessary to find the values of the partial derivatives Em (m,b) and Eb (m,b). Find these values. (Xn² Yn) •(X3, Y3)

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Least squares approximation is a method for finding the
line with minimum vertical distance from a set of points.
Let the equation of the best-fit line be y = mx + b, where
the slope m and the y-intercept b must be determined
using the least squares condition. Assume there are
three data points (1,2), (2,3), and (3,5). The following
function E(m,b) represents the sums of the squares of
the vertical distances of each point from the best-fit line.
Find the critical points of E and find the values of m and b
that minimize E. Graph the three data points and
the best-fit line.
E(m,b) = [(m + b) – 2]² + [(2m + b) − 3]² + [(3m + b) – 5]²
y
(Xn-1* Yn-1)
Em (m,b) =
Eb (m,b) =
(Simplify your answer. Do not factor.)
regression
line
(x₁, y₁)
(X₂² Y₂)
To find the critical points, it will first be necessary to find the values of the partial
derivatives Em (m,b) and E₁ (m,b). Find these values.
(Xn² Yn)
• (X3, Y3)
Transcribed Image Text:Least squares approximation is a method for finding the line with minimum vertical distance from a set of points. Let the equation of the best-fit line be y = mx + b, where the slope m and the y-intercept b must be determined using the least squares condition. Assume there are three data points (1,2), (2,3), and (3,5). The following function E(m,b) represents the sums of the squares of the vertical distances of each point from the best-fit line. Find the critical points of E and find the values of m and b that minimize E. Graph the three data points and the best-fit line. E(m,b) = [(m + b) – 2]² + [(2m + b) − 3]² + [(3m + b) – 5]² y (Xn-1* Yn-1) Em (m,b) = Eb (m,b) = (Simplify your answer. Do not factor.) regression line (x₁, y₁) (X₂² Y₂) To find the critical points, it will first be necessary to find the values of the partial derivatives Em (m,b) and E₁ (m,b). Find these values. (Xn² Yn) • (X3, Y3)
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