lease make a lab report (Newton's law) Abstract:-  The goal for this experiment is to show that the acceleration is directly proportional to the net force in part A. And part B, we need to show the acceleration is inversely proportional to the mass, and the acceleration is directly proportional to the product of Force and one

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Please make a lab report (Newton's law)

Abstract:-  The goal for this experiment is to show that the acceleration is directly proportional to the net force in part A. And part B, we need to show the acceleration is inversely proportional to the mass, and the acceleration is directly proportional to the product of Force and one over mass.

This is my data.

A
В
E
5 Table 1
constant mass
6.
ave
7
M1
m2
net force mass system
аcc th
distance
time
асс еxpt
8
20
15
49
35
1.4
0.7
7.3
0.03
10
25
10
147
35
4.2
0.7
0.9
1.73
11
30
245
35
7
0.7
0.58
4.16
12
13
The dependence of the acceleration on the net force
14
y = 0.0211x - 1.1295
4.50
R? = 0.9897
15
4.00
16
3.50
17
3.00
18
19
2.50
20
2.00
21
1.50
22
1.00
23
0.50
24
0.00
25
50
100
150
200
250
300
26
-0.50
Net Force(N)
27
ose
acceleration(m/s^2)
Transcribed Image Text:A В E 5 Table 1 constant mass 6. ave 7 M1 m2 net force mass system аcc th distance time асс еxpt 8 20 15 49 35 1.4 0.7 7.3 0.03 10 25 10 147 35 4.2 0.7 0.9 1.73 11 30 245 35 7 0.7 0.58 4.16 12 13 The dependence of the acceleration on the net force 14 y = 0.0211x - 1.1295 4.50 R? = 0.9897 15 4.00 16 3.50 17 3.00 18 19 2.50 20 2.00 21 1.50 22 1.00 23 0.50 24 0.00 25 50 100 150 200 250 300 26 -0.50 Net Force(N) 27 ose acceleration(m/s^2)
D E
A
В
F
G
K
31 Tabel 2 dependence of acceleration on the total mass of system
32
33
M1
m2
net force mass system
acc th
distance
time
асс ехpt
1/Mass
асс
34
35
10
5
49
15
3.3
0.7
1.74
0.46
0.067
0.462
36
15
10
49
25
2.0
0.7
2.26
0.27
0.040
0.274
37
20
15
49
35
1,4
0.7
2.94
0.16
0.029
0.162
38
39
The dependence of the acceleration on the mass
40
0.500
41
y = 7.7404x -0.0494
0.450
42
R2 = 0.9934
0.400
43
0.350
44
0.300
45
0.250
46
0.200
47
0.150
48
0.100
49
0.050
50
0.000
51
0.000
0.020
0.040
0.060
0.080
52
inverse mass
acceleration(m/s^2)
Transcribed Image Text:D E A В F G K 31 Tabel 2 dependence of acceleration on the total mass of system 32 33 M1 m2 net force mass system acc th distance time асс ехpt 1/Mass асс 34 35 10 5 49 15 3.3 0.7 1.74 0.46 0.067 0.462 36 15 10 49 25 2.0 0.7 2.26 0.27 0.040 0.274 37 20 15 49 35 1,4 0.7 2.94 0.16 0.029 0.162 38 39 The dependence of the acceleration on the mass 40 0.500 41 y = 7.7404x -0.0494 0.450 42 R2 = 0.9934 0.400 43 0.350 44 0.300 45 0.250 46 0.200 47 0.150 48 0.100 49 0.050 50 0.000 51 0.000 0.020 0.040 0.060 0.080 52 inverse mass acceleration(m/s^2)
Expert Solution
Step 1

Given:-

We have given the two graphs of  acceleration vs Net force  and The acceleration vs inverse mass 

Find:-

show the acceleration is inversely proportional to the mass, and the acceleration is directly proportional to the product of Force and one over mass.

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