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Learning Target N2 (Core): I can perform back-substitution in the Euclidean Algorithm to write the the greatest common divisor of a and b as in Bézout's Lemma, gcd(a, b) =as + bt, noting the between the terms with a, b, s, te Z Use the Euclidean Algorithm with back-substitution to find the gcd (a, b) and then write gcd (a, b) = as+bt, making sure to have the + between the terms. 1. a 49, b= 15. The answer is 1 = 49. (4) +15(-13), now show the work. 2. a = 836, b= 253. The answer is 11 = 836 (10) + 253 (-33), now show the work.

Learning Target N2 (Core): I can perform back-substitution in the Euclidean Algorithm to write the the greatest common divisor of a and b as in Bézout's Lemma, gcd(a, b) =as + bt, noting the between the terms with a, b, s, te Z Use the Euclidean Algorithm with back-substitution to find the gcd (a, b) and then write gcd (a, b) = as+bt, making sure to have the + between the terms. 1. a 49, b= 15. The answer is 1 = 49. (4) +15(-13), now show the work. 2. a = 836, b= 253. The answer is 11 = 836 (10) + 253 (-33), now show the work.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Learning Target N2 (Core): I can perform back-substitution in the Euclidean Algorithm to write the the greatest common divisor of a and b as in Bézout's Lemma, gcd(a, b) = as+bt, noting the between the terms with a, b, s, te Z Use the Euclidean Algorithm with back-substitution to find the gcd(a, b) and then write gcd(a, b) = as+bt, making sure to have the + between the terms. 1. a = 49, b = 15. The answer is 1 = 49. (4) +15 (13), now show the work. 2. a = 836, b = 253. The answer is 11 = 836 (10) +253 (-33), now show the work.
Transcribed Image Text:Learning Target N2 (Core): I can perform back-substitution in the Euclidean Algorithm to write the the greatest common divisor of a and b as in Bézout's Lemma, gcd(a, b) = as+bt, noting the between the terms with a, b, s, te Z Use the Euclidean Algorithm with back-substitution to find the gcd(a, b) and then write gcd(a, b) = as+bt, making sure to have the + between the terms. 1. a = 49, b = 15. The answer is 1 = 49. (4) +15 (13), now show the work. 2. a = 836, b = 253. The answer is 11 = 836 (10) +253 (-33), now show the work.
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