Learning Goal: To understand and apply the formula T = Ia to rigid objects rotating about a fixed axis. To find the acceleration a of a particle of mass m, we use Newton's second law: Fnet = ma, where Fnet is the net force acting on the particle. To find the angular acceleration a of a rigid object rotating about a fixed axis, we can use a similar formula: Thet= Ia, where Thet Στ is the net torque acting on the object and I is its moment of inertia. Figure m1 1 of 2 Part C Now consider a similar situation, except that now the swing bar itself has mass mbar-(Figure 2) Find the magnitude of the angular acceleration a of the seesaw. Express your answer in terms of some or all of the quantities m₁, m2, mbar, l, as well as the acceleration due to gravity g. ► View Available Hint(s) a = Submit Part D V—| ΑΣΦ 1 ? In what direction will the seesaw rotate and what will the sign of the angular acceleration be? O The rotation is in the clockwise direction and the angular acceleration is positive. O The rotation is in the clockwise direction and the angular acceleration is negative. O The rotation is in the counterclockwise direction and the angular acceleration is positive. O The rotation is in the counterclockwise direction and the angular acceleration is negative. Submit Request Answer

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Help with this would be great, thanks!

**Learning Goal:**
To understand and apply the formula \( \tau = I\alpha \) to rigid objects rotating about a fixed axis.

To find the acceleration \( a \) of a particle of mass \( m \), we use Newton’s second law: \( \vec{F}_{\text{net}} = m\vec{a} \), where \( \vec{F}_{\text{net}} \) is the net force acting on the particle. To find the angular acceleration \( \alpha \) of a rigid object rotating about a fixed axis, we can use a similar formula: \( \tau_{\text{net}} = I\alpha \), where \( \tau_{\text{net}} = \sum \tau \) is the net torque acting on the object and \( I \) is its moment of inertia.

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**Figure:**

The figure shows a seesaw balanced on a fulcrum, with distances labeled \( l \) and masses \( m_1 \) and \( m_2 \) positioned at opposite ends.

---

**Part C:**

Now consider a similar situation, except that now the swing bar itself has mass \( m_{\text{bar}} \). (Figure 2) Find the magnitude of the angular acceleration \( \alpha \) of the seesaw.

Express your answer in terms of some or all of the quantities \( m_1, m_2, m_{\text{bar}}, l \), as well as the acceleration due to gravity \( g \).

- **Expression Box:** 
  - Alpha \( \alpha = \) [Input box for answer]

- **Submit Button**

---

**Part D:**

In what direction will the seesaw rotate and what will the sign of the angular acceleration be?

- **Options:**
  - The rotation is in the clockwise direction and the angular acceleration is positive.
  - The rotation is in the clockwise direction and the angular acceleration is negative.
  - The rotation is in the counterclockwise direction and the angular acceleration is positive.
  - The rotation is in the counterclockwise direction and the angular acceleration is negative.

- **Submit Button**
- **Request Answer**

---
Transcribed Image Text:**Learning Goal:** To understand and apply the formula \( \tau = I\alpha \) to rigid objects rotating about a fixed axis. To find the acceleration \( a \) of a particle of mass \( m \), we use Newton’s second law: \( \vec{F}_{\text{net}} = m\vec{a} \), where \( \vec{F}_{\text{net}} \) is the net force acting on the particle. To find the angular acceleration \( \alpha \) of a rigid object rotating about a fixed axis, we can use a similar formula: \( \tau_{\text{net}} = I\alpha \), where \( \tau_{\text{net}} = \sum \tau \) is the net torque acting on the object and \( I \) is its moment of inertia. --- **Figure:** The figure shows a seesaw balanced on a fulcrum, with distances labeled \( l \) and masses \( m_1 \) and \( m_2 \) positioned at opposite ends. --- **Part C:** Now consider a similar situation, except that now the swing bar itself has mass \( m_{\text{bar}} \). (Figure 2) Find the magnitude of the angular acceleration \( \alpha \) of the seesaw. Express your answer in terms of some or all of the quantities \( m_1, m_2, m_{\text{bar}}, l \), as well as the acceleration due to gravity \( g \). - **Expression Box:** - Alpha \( \alpha = \) [Input box for answer] - **Submit Button** --- **Part D:** In what direction will the seesaw rotate and what will the sign of the angular acceleration be? - **Options:** - The rotation is in the clockwise direction and the angular acceleration is positive. - The rotation is in the clockwise direction and the angular acceleration is negative. - The rotation is in the counterclockwise direction and the angular acceleration is positive. - The rotation is in the counterclockwise direction and the angular acceleration is negative. - **Submit Button** - **Request Answer** ---
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