I am stuck on Parts C,D,E. Please help :)) >Learning Goal:To find a position vector between two arbitrary points.As shown, two cables connect three points. C isbelow A by a distance Cz = 1.30 ft andconnected to A by a cable 12.3 ft long. Cable ACforms an angle = 21.0° with the positive y axis. Bis 8.70 ft above C and the distances B and Byare 8.90 ft and 5.90 ft, respectively. (Figure 1)FigureBByB< 1 of 1Cxy▼Part C - Position vector from A to CThe length of cable AC is 12.3 ft, and the cable forms the angle ß = 21.0° with the y axis. Given this information and thedimensions provided in the figure, find the position vector from A to C. Express the position vector in component form.Express your answers, separated by commas, to three significant figures.► View Available Hint(s)rAC =Submit Request AnswerVE ΑΣΦPart D - Position vector from B to CrBC||↓↑ vecΠ ΑΣΦFind the position vector from B to C. Express your answer in component form.Express your answers, separated by commas, to three significant figures.► View Available Hint(s)↓↑P Pearson....vec?i ft, j ft, k ft?ift, jft, k ft Part E-Tension in the cableA cable is attached between B and C. The cable is attached in such a way that it has a tension of TBC along its length. Thetensile force will attempt to pull B toward C. The force exerted on B has a z component with a magnitude of 10 lb . What isthe magnitude of the tension in the cable, TBC?Express your answer to three significant figures and include the appropriate units.► View Available Hint(s)TBCSubmitProvide FeedbackμᾶValueP PearsonUnits?Next >

Given- Cz=13ftrac =12.3ftβ=21°Bx=8.9ftBy=5.9ftl=8.7ft

Learning Goal: To find a position vector between two arbitrary points. As shown, two cables connect three points. C' is below A by a distance C₂ = 1.30 ft and connected to A by a cable 12.3 ft long. Cable AC forms an angle B = 21.0° with the positive y axis. B is 8.70 ft above C' and the distances B₂ and By are 8.90 ft and 5.90 ft, respectively. (Figure 1) Figure C. 1 of 1 > ▼ The length of cable AC is 12.3 ft, and the cable forms the angle 3 = 21.0° with the y axis. Given this information and the dimensions provided in the figure, find the position vector from A to C. Express the position vector in component form. Express your answers, separated by commas, to three significant figures. ► View Available Hint(s) TAC = Submit [5] ΑΣΦ | 11 Request Answer TBC = Part D - Position vector from B to C vec [5] ΑΣΦ | H Find the position vector from B to C. Express your answer in component form. Express your answers, separated by commas, to three significant figures. ► View Available Hint(s) ? vec ift, j ft, k ft ? ift, j ft, k ft

Learning Goal: To find a position vector between two arbitrary points. As shown, two cables connect three points. C' is below A by a distance C₂ = 1.30 ft and connected to A by a cable 12.3 ft long. Cable AC forms an angle B = 21.0° with the positive y axis. B is 8.70 ft above C' and the distances B₂ and By are 8.90 ft and 5.90 ft, respectively. (Figure 1) Figure C. 1 of 1 > ▼ The length of cable AC is 12.3 ft, and the cable forms the angle 3 = 21.0° with the y axis. Given this information and the dimensions provided in the figure, find the position vector from A to C. Express the position vector in component form. Express your answers, separated by commas, to three significant figures. ► View Available Hint(s) TAC = Submit [5] ΑΣΦ | 11 Request Answer TBC = Part D - Position vector from B to C vec [5] ΑΣΦ | H Find the position vector from B to C. Express your answer in component form. Express your answers, separated by commas, to three significant figures. ► View Available Hint(s) ? vec ift, j ft, k ft ? ift, j ft, k ft

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter2: Vectors

Section: Chapter Questions

Problem 38P: Suppose you walk 18.0 m straight west and then 25.0 m straight north. How far are you from your...

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