Learning Diagnostic Analytics Recommendations Skill plans Math Common Core You have prizes Algebra 2 > T.12 Exponential growth and decay: word problems TYQ You have 8,560 grams of a radioactive kind of rubidium. If its half-life is 15 minutes, how much will be left after 45 minutes? grams Submit

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Exponential Growth and Decay: Word Problems

#### Algebra 2
#### T.12 Exponential Growth and Decay: Word Problems

**Problem:**

You have 8,560 grams of a radioactive kind of rubidium. If its half-life is 15 minutes, how much will be left after 45 minutes?

**Answer Box:**

```
[            ] grams
```

**Actions:**

- After entering your answer, click the "Submit" button.

**Concept Explanation:**

To solve this problem, use the formula for exponential decay:

\[ N(t) = N_0 \times \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \]

Where:
- \( N(t) \) is the remaining quantity of the substance after time \( t \).
- \( N_0 \) is the original quantity of the substance.
- \( t \) is the elapsed time.
- \( t_{1/2} \) is the half-life of the substance.

For this problem:
- \( N_0 = 8,560 \) grams.
- \( t = 45 \) minutes.
- \( t_{1/2} = 15 \) minutes.

Using the formula, we can calculate the remaining quantity of rubidium after 45 minutes.
Transcribed Image Text:### Exponential Growth and Decay: Word Problems #### Algebra 2 #### T.12 Exponential Growth and Decay: Word Problems **Problem:** You have 8,560 grams of a radioactive kind of rubidium. If its half-life is 15 minutes, how much will be left after 45 minutes? **Answer Box:** ``` [ ] grams ``` **Actions:** - After entering your answer, click the "Submit" button. **Concept Explanation:** To solve this problem, use the formula for exponential decay: \[ N(t) = N_0 \times \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \] Where: - \( N(t) \) is the remaining quantity of the substance after time \( t \). - \( N_0 \) is the original quantity of the substance. - \( t \) is the elapsed time. - \( t_{1/2} \) is the half-life of the substance. For this problem: - \( N_0 = 8,560 \) grams. - \( t = 45 \) minutes. - \( t_{1/2} = 15 \) minutes. Using the formula, we can calculate the remaining quantity of rubidium after 45 minutes.
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