EXAMPLE 8.5 Locating Your Lab Partner's Center of GravityGOAL Use torque to find a centerof gravity.PROBLEM In this example weshow how to find the location of aperson's center of gravity. Supposeyour lab partner has a height L of173 cm (5 ft, 8 in) and a weight w of715 N (160 lb). You can determinethe position of his center of gravityby having him stretch out on auniform board supported at one endby a scale, as shown in the figure. If the board's weight w, is 49 N and the scale reading ♬ is 3.50 × 10²N, find the distance of your lab partner's center of gravity from the left end of the board.SOLUTIONApply the second condition ofequilibrium.Substitute expressions for the torques.Solve for xvalues.cg0and substitute knownSTRATEGY To find the position xcg of the center of gravity, compute the torques using an axis throughO. There is no torque due to the normal forcen because its moment arm is zero about an axis through O.Set the sum of the torques equal to zero and solve for xx cg*Determining your lab partner's center of gravity.0Στ; = τη + τnX-L/2Xcgcg==+ τ.WWbwbWXcg - W₂(L/2) + FL = 0FL - W (L/2)W(350 N) (173 cm) – (49 N)(86.5 cm)715 NTF = 0TE= 79 cm LEARN MOREREMARKS The given information is sufficient only to determine the x-coordinate of the center ofgravity. The other two coordinates can be estimated, based on the body's symmetry.QUESTION What would happen if a support is placed exactly at x = 79 cm followed by the removal ofthe supports at the subject's head and feet? (Assume the board is removed along with the supports.Select all that apply.)The subject's head would sink toward the ground.The subject's center of gravity would shift toward his head.The subject's center of gravity would not shift.The subject's feet would sink toward the ground.The subject would remain balanced.The subject's center of gravity would shift toward his feet.

Name: EXAMPLE 8.5 Locating Your Lab Partner's Center of GravityGOAL Use tor
Uploaded: 2024-03-20T06:51:10.000Z
Channel: Bartleby
Description: EXAMPLE 8.5 Locating Your Lab Partner's Center of GravityGOAL Use torque to find a centerof gravity.PROBLEM In this example weshow how to find the location of aperson's center of gravity. Supposeyour lab partner has a height L of173 cm (5 ft, 8 in)

Answered: Image /qna-images/answer/f9413294-4d99-4067-949a-65cfab48de70.jpg

Science

Physics

LEARN MORE REMARKS The given information is sufficient only to determine the x-coordinate of the center of gravity. The other two coordinates can be estimated, based on the body's symmetry. QUESTION What would happen if a support is placed exactly at x = 79 cm followed by the removal of the supports at the subject's head and feet? (Assume the board is removed along with the supports. Select all that apply.) The subject's head would sink toward the ground. The subject's center of gravity would shift toward his head. The subject's center of gravity would not shift. The subject's feet would sink toward the ground. The subject would remain balanced. The subject's center of gravity would shift toward his feet. ооооо

LEARN MORE REMARKS The given information is sufficient only to determine the x-coordinate of the center of gravity. The other two coordinates can be estimated, based on the body's symmetry. QUESTION What would happen if a support is placed exactly at x = 79 cm followed by the removal of the supports at the subject's head and feet? (Assume the board is removed along with the supports. Select all that apply.) The subject's head would sink toward the ground. The subject's center of gravity would shift toward his head. The subject's center of gravity would not shift. The subject's feet would sink toward the ground. The subject would remain balanced. The subject's center of gravity would shift toward his feet. ооооо

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A uniform 6.59 m long horizontal beam that weighs 269 N is attached to a wall by a pin connection…

Q: One end of a uniform, 4-m-long rod of weight, W, is supported by a string. The other end is resting…

Q: The drum has a weight of 150 lb and rests on the floor for which the coefficient of static friction…

A: When a body of mass m resting on the non-frictionless floor (horizontal/vertical/inclined) is…

Q: A sound wave moves through a medium with density 480kg/m^3 when it encounters a medium with density…

Q: Suppose I install a shelf in my bedroom for my awesome CD collection. In order to reach this shelf,…

A: The objective of the question is to determine the force exerted on the board by each brick when a…

Q: 30 50n 4.00 m Figure 1 ON

A: Draw the free-body diagram of the system.

Q: An exhaust system for a pickup truck is shown in the figure. The weights Wh, Wm, and w, of the…

A: SOlution: Given that

Q: When the structure shown below is supPported direction of the force applied at P. The weight of the…

A: a) For rotational equilibrium about the pivot point P. CCW moment = CW moment. (2200*1.9) =…

Q: A 15.0 kg sign hangs from the end of a beam of length of 2.50 meters and mass 25.0 kg as shown in…

A: Given: The beam of the cable is 2.5 m. The mass of the beam is 25 kg. The length of the cable is 3.5…

Q: Find the x- and y-coordinates of the center of gravity for the boomerang as in (a) of the figure…

A: Length , L = 0.232 mMass, m = 0.290 kgTo find = x and y co-ordinates of center of gravity of the…

Q: The centers of gravity of the three trucks parked on a hill are shown by the star. Which truck will…

A: The normal force and frictional force acting on all the three trucks will be the same.The position…

Q: A 20.0-m-long uniform beam weighing 700 N rests on walls A and B, as shown in the figure below. с…

Q: A uniform crate with a mass of 39 kg must be moved up along the 15 incline without tipping. The…

Q: What is the final angle θf that the ball's velocity vector makes with the negative y axis?

A: Given, A ball of mass m moving with velocity v→i strikes a vertical wall. The angle between the…

Q: A double-decker London bus (Figure 1) might be in danger of rolling over in a highway accident, but…

Q: Determine the tension in the cable.

A: Newton's Second Law of Motion for rotation The net torque acting on a system is equal to the product…

Q: 1 540-kg automobile has a wheel base (the distance between the axles) of 3.10 m. The automobile's…

Q: Solve this question please. Don't use chat gpt.

A: Given Data:- Weight on the front axle (Wf) = 1040 kg- Weight on the rear axle (Wr) = 595 kg-…

Q: Solve the problem correctly. Include diagram if possible

A: Given Data:- Weight on the front axle (Wf) = 1040 kg- Weight on the rear axle (Wr) = 595 kg-…

Q: Consider the objects on the coordinate grid: a rod with m1 = 7.75 kg, a right triangle with m2 =…

A: Given that, Mass of rod(m1)= 7.75 kg Mass of right triangle (m2)= 26.0 kg, and mass of square (m3) =…

Q: A ladder of length L and mass m makes a θ degree angle with a wall. The center of mass of this…

A: Given, The center of mass of this ladder is 1/3 of the way up from the bottom a.

Q: Determine the location of the centre of gravity from point O, of a horizontalbeam consisting of 4…

A: Center of mass or center of gravity is just a mathematical point and concept. Center of gravity is…

Concept explainers

Fluid Pressure

The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.

Gauge Pressure

Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem to bother anyone as the bodily fluids are constantly pushing outwards with the same force but if one swims down into the ocean a few feet below the surface one can notice the difference, there is increased pressure on the eardrum, this is due to an increase in hydrostatic pressure.

Topic Video

Question

EXAMPLE 8.5 Locating Your Lab Partner's Center of Gravity
GOAL Use torque to find a center
of gravity.
PROBLEM In this example we
show how to find the location of a
person's center of gravity. Suppose
your lab partner has a height L of
173 cm (5 ft, 8 in) and a weight w of
715 N (160 lb). You can determine
the position of his center of gravity
by having him stretch out on a
uniform board supported at one end
by a scale, as shown in the figure. If the board's weight w, is 49 N and the scale reading ♬ is 3.50 × 10²
N, find the distance of your lab partner's center of gravity from the left end of the board.
SOLUTION
Apply the second condition of
equilibrium.
Substitute expressions for the torques.
Solve for x
values.
cg
0
and substitute known
STRATEGY To find the position xcg of the center of gravity, compute the torques using an axis through
O. There is no torque due to the normal forcen because its moment arm is zero about an axis through O.
Set the sum of the torques equal to zero and solve for x
x cg*
Determining your lab partner's center of gravity.
0
Στ; = τη + τ
n
X
-
L/2
Xcg
cg
=
=
+ τ.
W
Wb
wb
WXcg - W₂(L/2) + FL = 0
FL - W (L/2)
W
(350 N) (173 cm) – (49 N)(86.5 cm)
715 N
TF = 0
TE
= 79 cm

LEARN MORE
REMARKS The given information is sufficient only to determine the x-coordinate of the center of
gravity. The other two coordinates can be estimated, based on the body's symmetry.
QUESTION What would happen if a support is placed exactly at x = 79 cm followed by the removal of
the supports at the subject's head and feet? (Assume the board is removed along with the supports.
Select all that apply.)
The subject's head would sink toward the ground.
The subject's center of gravity would shift toward his head.
The subject's center of gravity would not shift.
The subject's feet would sink toward the ground.
The subject would remain balanced.
The subject's center of gravity would shift toward his feet.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

Suppose a horse leans against a wall as shown in the figure. The total of the horse and rider is 500 kg. Part a : calculate the magnitude of the force in newtons on each foot of the horse in the figure assuming the center of the mass of the horse between and the weight is equally divided between the two feet on the ground. Part b: what is the minimum coefficient of friction between the hooves and ground? Note that the force exerted by the wall is horizontal.
A 1 555-kg automobile has a wheel base (the distance between the axles) of l = 2.85 m. The automobile's center of mass is on the centerline at a point 1.35 m behind the front axle. Find the force exerted by the ground on each wheel. Part 1 of 3 - Conceptualize Since the center of mass is located in the front half of the car, there should be more force on the front wheels than the rear ones. The sum of the wheel forces must equal the weight of the car. Part 2 of 3 - Categorize Use the figure as a force diagram. Apply Newton's second law and sum the torques to find the unknown forces. l Part 3 of 3 - Analyze The torque about the front axle is zero, so we have Στις = 0 = (d Fg) - l (2F₁). Thus the force at each rear wheel is given by d F F₁ = 2Ff g || d 21 2F, m)(1. X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step da N. Since the sum of the wheel forces equals the weight of the car, we have 2F₁ + 2F₁ = Fg.…
Chapter 12, Problem 002 An automobile with a mass of 1350.00 kg has 3.35 m between the front and rear axles. Its center of gravity is located 0.456 m behind the front axle. With the automobile on level ground, determine the magnitude of the force from the ground on (a) each front wheel (assuming equal forces on the front wheels) and (b) each rear wheel (assuming equal forces on the rear wheels). (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work LINK TO TEXT LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE
Three identical coins lie on three corners of a square a = 11.0 cm on a side, as shown in (Figure 1). Determine the x coordinate of the center of gravity of the three coins. Express your answer with the appropriate units. Determine the y coordinate of the center of gravity of the three coins. Express your answer with the appropriate units.
The door has a weight of 230 lb and a center of gravity at G. (Bouto 1) Figure ▼ Part C NA = 1 of 1 HÅ Value Determine the constant force F that must be applied to the door to push it open 19.0 ft to the right in 5 s. starting from rest. Express your answer to three significant figures and include the appropriate units. Submit Request Answer Part B. Value Units Submit Previous Answers Request Answer X Incorrect: Try Again; 5 attempts remaining μA Also, find the vertical reaction at the roller B Express your answer to three significant figures and include the appropriate units. No - Value Submit Also, find the vertical reaction at the roller A. Express your answer to three significant figures and include the appropriate units. Previous Answers Request Answer Units Units ?
A person is pushing a fully loaded 25.40 kg wheelbarrow at constant velocity along a plank that makes an angle a = 32.0° with the horizontal. The load is distributed such that the center of mass of the wheelbarrow is exactly halfway along its length L. What is the magnitude of the total force F, the person must apply so that the wheelbarrow is parallel to that plank? You may neglect the radius of the wheel in your analysis. The F. gravitational acceleration is g = 9.81 m/s². F = N
Hand written and clean answer