Lead(II) oxide can be reduced to form elemental lead through the reaction: PbO(s) + C(s) → Pb(s) + CO(g) Calculate AH° for the above reaction given the following (all values are at 25°C):

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Lead(II) oxide can be reduced to form elemental lead through the reaction:

\[ \text{PbO}(s) + \text{C}(s) \rightarrow \text{Pb}(s) + \text{CO}(g) \]

Calculate \(\Delta H^\circ\) for the above reaction given the following (all values are at \(25^\circ \text{C}\)):
Transcribed Image Text:Lead(II) oxide can be reduced to form elemental lead through the reaction: \[ \text{PbO}(s) + \text{C}(s) \rightarrow \text{Pb}(s) + \text{CO}(g) \] Calculate \(\Delta H^\circ\) for the above reaction given the following (all values are at \(25^\circ \text{C}\)):
**Thermochemical Equation Manipulation**

In this example, we will explore how to manipulate thermochemical equations to find the enthalpy change (\( \Delta H^\circ \)) for a given reaction.

1. **Reaction Equations and \(\Delta H^\circ\):**

   - Equation 1:
     \[
     2 \, \text{CO}(g) + \cancel{\text{O}_2(g)} \rightarrow 2 \, \text{CO}_2(g) \quad \Delta H^\circ = -566.0 \, \text{kJ}
     \]

   - Equation 2:
     \[
     2 \, \text{NO}(g) \rightarrow \text{N}_2(g) + \cancel{\text{O}_2(g)} \quad \Delta H^\circ = -180.5 \, \text{kJ}
     \]

2. **Overall Reaction:**

   The overall chemical reaction is derived by combining the above equations and eliminating common species on both sides:

   \[
   2 \, \text{CO}(g) + 2 \, \text{NO}(g) \rightarrow 2 \, \text{CO}_2(g) + \text{N}_2(g)
   \]

3. **Overall Enthalpy Change:**

   The overall enthalpy change is the sum of the enthalpy changes from each individual reaction:

   \[
   \Delta H^\circ = -746.5 \, \text{kJ}
   \]

This demonstrates the principle of Hess's Law, where the total enthalpy change is the sum of the enthalpy changes of individual steps, allowing you to calculate the enthalpy for a desired reaction from known values.
Transcribed Image Text:**Thermochemical Equation Manipulation** In this example, we will explore how to manipulate thermochemical equations to find the enthalpy change (\( \Delta H^\circ \)) for a given reaction. 1. **Reaction Equations and \(\Delta H^\circ\):** - Equation 1: \[ 2 \, \text{CO}(g) + \cancel{\text{O}_2(g)} \rightarrow 2 \, \text{CO}_2(g) \quad \Delta H^\circ = -566.0 \, \text{kJ} \] - Equation 2: \[ 2 \, \text{NO}(g) \rightarrow \text{N}_2(g) + \cancel{\text{O}_2(g)} \quad \Delta H^\circ = -180.5 \, \text{kJ} \] 2. **Overall Reaction:** The overall chemical reaction is derived by combining the above equations and eliminating common species on both sides: \[ 2 \, \text{CO}(g) + 2 \, \text{NO}(g) \rightarrow 2 \, \text{CO}_2(g) + \text{N}_2(g) \] 3. **Overall Enthalpy Change:** The overall enthalpy change is the sum of the enthalpy changes from each individual reaction: \[ \Delta H^\circ = -746.5 \, \text{kJ} \] This demonstrates the principle of Hess's Law, where the total enthalpy change is the sum of the enthalpy changes of individual steps, allowing you to calculate the enthalpy for a desired reaction from known values.
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