Lead metal is obtained from lead sulfide through the following reaction : 2PBS(s) + 2C(s) + 302 (g) →2PB(s) + 2C0(g) + 25o2 (g)z a) If 100g Of PbS is reacted with excess C and O2, calculate the mass of lead metal obtained. b) Suppose 100g of PbS is reacted with 4g of C and 20g O2. Find the limiting reactant for this reaction. c) For question (b) above, calculate the mass of lead metal obtained. d) By referring to the question (c) above, If 31.2g Pb is obtained as the yield. Calculate the percentage of yield. e) Calculate mass of oxygen is needed to produce 500g of lead metal.

Lead metal is obtained from lead sulfide through the following reaction : 2PBS(s) + 2C(s) + 302 (g) →2PB(s) + 2C0(g) + 25o2 (g)z a) If 100g Of PbS is reacted with excess C and O2, calculate the mass of lead metal obtained. b) Suppose 100g of PbS is reacted with 4g of C and 20g O2. Find the limiting reactant for this reaction. c) For question (b) above, calculate the mass of lead metal obtained. d) By referring to the question (c) above, If 31.2g Pb is obtained as the yield. Calculate the percentage of yield. e) Calculate mass of oxygen is needed to produce 500g of lead metal.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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