Lead (II) sulfide reacts with hydrogen peroxide (H2O2) to give lead (II) sulfate and water. a. Write a balanced equation for the reaction. __________________________________________________ b. If 63.2 g of PbS is reacted with 48.0 g of H2O2 how many grams of PbSO4 would be produced if the reaction had an 76.0% yield? Hint: First find the limiting reactant, then find the theoretical yield. Molecular masses: PbS = 239.3 amu, H2O2 = 34.02 amu, PbSO4 = 303.3 amu, H2O = 18.02 amu What is the limiting reagent? _____________________________ Grams of PbSO4 _____________________________

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