Lead (II) nitrate is reacted with sodium iodide. Calculate the number of Pb* ions required to form 0.87 g of precipitate. Write the balanced molecular, total ionic, and net ionic equations of the reaction. Atomic Mass: Pb: 207.2 g/mol N: 14.0067 g/mol 0: 15.999 g/mol Na: 22.989769 g/mol 1:126.90447 g/mol Note: Use scientific notation with the format (n)e(x) where n = number and x = exponent (Example: 6.022e23 for 6.022 x 1023) Round your answer to 4 decimal places.

Lead (II) nitrate is reacted with sodium iodide. Calculate the number of Pb* ions required to form 0.87 g of precipitate. Write the balanced molecular, total ionic, and net ionic equations of the reaction. Atomic Mass: Pb: 207.2 g/mol N: 14.0067 g/mol 0: 15.999 g/mol Na: 22.989769 g/mol 1:126.90447 g/mol Note: Use scientific notation with the format (n)e(x) where n = number and x = exponent (Example: 6.022e23 for 6.022 x 1023) Round your answer to 4 decimal places.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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