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LDA 2) 0 H&H 3) H30t

LDA 2) 0 H&H 3) H30t

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the major product?

### Chemical Reaction Process **Starting Material:** - Cyclohexanone, represented by a six-membered carbon ring with a ketone group (C=O) attached to one of the carbons. **Reagents and Conditions:** 1. **LDA (Lithium Diisopropylamide):** A strong, non-nucleophilic base often used to deprotonate at the alpha position (the carbon adjacent to the carbonyl group). 2. **Formaldehyde (H₂C=O):** A simple aldehyde used as a reagent in this reaction. 3. **H₃O⁺ (Hydronium Ion):** Used to protonate or neutralize the reaction mixture. ### Explanation: This reaction typically involves the formation of an enolate anion when LDA deprotonates the alpha hydrogen of cyclohexanone. This enolate can then attack the electrophilic carbon of formaldehyde, forming a new carbon-carbon bond. Finally, the addition of hydronium ion (H₃O⁺) in the last step generally serves to protonate the oxygen to stabilize the final product. This sequence is characteristic of an Aldol reaction, where an aldehyde (formaldehyde) and a ketone (cyclohexanone) are used to form a β-hydroxy ketone. This type of reaction is widely used for creating complex molecules in organic synthesis, particularly in natural products and pharmaceuticals.
Transcribed Image Text:### Chemical Reaction Process **Starting Material:** - Cyclohexanone, represented by a six-membered carbon ring with a ketone group (C=O) attached to one of the carbons. **Reagents and Conditions:** 1. **LDA (Lithium Diisopropylamide):** A strong, non-nucleophilic base often used to deprotonate at the alpha position (the carbon adjacent to the carbonyl group). 2. **Formaldehyde (H₂C=O):** A simple aldehyde used as a reagent in this reaction. 3. **H₃O⁺ (Hydronium Ion):** Used to protonate or neutralize the reaction mixture. ### Explanation: This reaction typically involves the formation of an enolate anion when LDA deprotonates the alpha hydrogen of cyclohexanone. This enolate can then attack the electrophilic carbon of formaldehyde, forming a new carbon-carbon bond. Finally, the addition of hydronium ion (H₃O⁺) in the last step generally serves to protonate the oxygen to stabilize the final product. This sequence is characteristic of an Aldol reaction, where an aldehyde (formaldehyde) and a ketone (cyclohexanone) are used to form a β-hydroxy ketone. This type of reaction is widely used for creating complex molecules in organic synthesis, particularly in natural products and pharmaceuticals.
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