Laws passed in some states define a drunk driver as one who drives with blood alcohol level of 0.10% by mass or higher. The level of alcohol can be determined by titrating blood plasma with potassium dichromate to the following equation: (equation shown in picture). Assuming that the only substance that reacts with dichromate import plasma is alcohol, is a person legally drunk if 38.94 mL of 0.0723 M potassium take him he is required to titrate a 50.0 g sample of blood plasma
Laws passed in some states define a drunk driver as one who drives with blood alcohol level of 0.10% by mass or higher. The level of alcohol can be determined by titrating blood plasma with potassium dichromate to the following equation: (equation shown in picture). Assuming that the only substance that reacts with dichromate import plasma is alcohol, is a person legally drunk if 38.94 mL of 0.0723 M potassium take him he is required to titrate a 50.0 g sample of blood plasma
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Laws passed in some states define a drunk driver as one who drives with blood alcohol level of 0.10% by mass or higher. The level of alcohol can be determined by titrating blood plasma with potassium dichromate to the following equation: (equation shown in picture). Assuming that the only substance that reacts with dichromate import plasma is alcohol, is a person legally drunk if 38.94 mL of 0.0723 M potassium take him he is required to titrate a 50.0 g sample of blood plasma
![The level of alcohol can be determined by titrating blood plasma with potassium dichromate according to the following equation:
\[ \text{16H}^+\text{(aq)} + \text{2Cr}_2\text{O}_7^{2-}\text{(aq)} + \text{C}_2\text{H}_5\text{OH}\text{(aq)} \rightarrow \text{4Cr}^{3+}\text{(aq)} + \text{2CO}_2\text{(g)} + \text{11H}_2\text{O}\text{(l)} \]
Assuming that the only substance that reacts with dichromate in blood plasma is alcohol, is a person legally drunk if 38.94 mL of 0.0723 M potassium dichromate is required to titrate a 50.0-g sample of blood plasma?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F18727bec-9840-4f6f-93dd-d50a9a5fea6f%2Fab248dcb-4807-4337-97d0-e0de94c50be3%2Fyff2gk.jpeg&w=3840&q=75)
Transcribed Image Text:The level of alcohol can be determined by titrating blood plasma with potassium dichromate according to the following equation:
\[ \text{16H}^+\text{(aq)} + \text{2Cr}_2\text{O}_7^{2-}\text{(aq)} + \text{C}_2\text{H}_5\text{OH}\text{(aq)} \rightarrow \text{4Cr}^{3+}\text{(aq)} + \text{2CO}_2\text{(g)} + \text{11H}_2\text{O}\text{(l)} \]
Assuming that the only substance that reacts with dichromate in blood plasma is alcohol, is a person legally drunk if 38.94 mL of 0.0723 M potassium dichromate is required to titrate a 50.0-g sample of blood plasma?
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