Laura's g member crew could do j jobs in h hours. When q members went on vacation how many hours would it take the remaining crew members to do m jobs? (g- )m [A] gjh gmh [B] (g-4)j gm [C] (g-4)jh (g-q)mh [D] gj

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Please solve 15 and 16.

### Problem Statement

Laura’s \( g \)-member crew could do \( j \) jobs in \( h \) hours. When \( q \) members went on vacation, how many hours would it take for the remaining crew members to do \( m \) jobs?

### Options

\[ 
[A] \quad \frac{(g - q)m}{gjh}
\]

\[ 
[B] \quad \frac{gmh}{(g - q)j}
\]

\[ 
[C] \quad \frac{gm}{(g - q)jh}
\]

\[ 
[D] \quad \frac{(g - q)mh}{gj}
\]

### Explanation of Solutions

The problem involves understanding the relationship between crew size, the number of jobs, and the time taken. Here are the details of the given answer choices, explained:

1. **[A]**: 
   \[
   \frac{(g - q)m}{gjh}
   \]
   This expression calculates the required hours based on the product of the reduced crew size \((g - q)\) and the number of jobs \(m\), divided by the product of the full crew size \(g\), jobs \(j\), and initial hours \(h\).

2. **[B]**: 
   \[
   \frac{gmh}{(g - q)j}
   \]
   Here, the equation involves the product of the full crew size \(g\), hours \(h\), and the number of jobs \(m\), divided by the product of the reduced crew size \((g - q)\) and jobs \(j\).

3. **[C]**: 
   \[
   \frac{gm}{(g - q)jh}
   \]
   This formula calculates the required hours by multiplying the initial crew size \(g\) and the number of jobs \(m\), then dividing the result by the product of the reduced crew size \((g - q)\), jobs \(j\), and hours \(h\).

4. **[D]**: 
   \[
   \frac{(g - q)mh}{gj}
   \]
   In this option, the formula uses the product of the reduced crew size \((g - q)\), jobs \(m\), and hours \(h\), divided by the product of the full crew size \(g\
Transcribed Image Text:### Problem Statement Laura’s \( g \)-member crew could do \( j \) jobs in \( h \) hours. When \( q \) members went on vacation, how many hours would it take for the remaining crew members to do \( m \) jobs? ### Options \[ [A] \quad \frac{(g - q)m}{gjh} \] \[ [B] \quad \frac{gmh}{(g - q)j} \] \[ [C] \quad \frac{gm}{(g - q)jh} \] \[ [D] \quad \frac{(g - q)mh}{gj} \] ### Explanation of Solutions The problem involves understanding the relationship between crew size, the number of jobs, and the time taken. Here are the details of the given answer choices, explained: 1. **[A]**: \[ \frac{(g - q)m}{gjh} \] This expression calculates the required hours based on the product of the reduced crew size \((g - q)\) and the number of jobs \(m\), divided by the product of the full crew size \(g\), jobs \(j\), and initial hours \(h\). 2. **[B]**: \[ \frac{gmh}{(g - q)j} \] Here, the equation involves the product of the full crew size \(g\), hours \(h\), and the number of jobs \(m\), divided by the product of the reduced crew size \((g - q)\) and jobs \(j\). 3. **[C]**: \[ \frac{gm}{(g - q)jh} \] This formula calculates the required hours by multiplying the initial crew size \(g\) and the number of jobs \(m\), then dividing the result by the product of the reduced crew size \((g - q)\), jobs \(j\), and hours \(h\). 4. **[D]**: \[ \frac{(g - q)mh}{gj} \] In this option, the formula uses the product of the reduced crew size \((g - q)\), jobs \(m\), and hours \(h\), divided by the product of the full crew size \(g\
**Problem 5**

A dog traveled at \( c \) feet per minute for \( d \) feet and was 5 minutes late for an open gate. How fast should the dog have traveled in order to find the gate open?

**Options:**

[A] \[\frac{c}{d - 5c} \, \text{ft/min}\]

[B] \[\frac{dc}{d + 5c} \, \text{ft/min}\]

[C] \[\frac{d}{d + 5c} \, \text{ft/min}\]

[D] \[\frac{dc}{d - 5c} \, \text{ft/min}\]

This problem requires determining the correct speed the dog should have traveled to reach the gate on time, utilizing the given variables and delayed minutes. The correct expression should effectively incorporate the dog’s speed and the delay (5 minutes).
Transcribed Image Text:**Problem 5** A dog traveled at \( c \) feet per minute for \( d \) feet and was 5 minutes late for an open gate. How fast should the dog have traveled in order to find the gate open? **Options:** [A] \[\frac{c}{d - 5c} \, \text{ft/min}\] [B] \[\frac{dc}{d + 5c} \, \text{ft/min}\] [C] \[\frac{d}{d + 5c} \, \text{ft/min}\] [D] \[\frac{dc}{d - 5c} \, \text{ft/min}\] This problem requires determining the correct speed the dog should have traveled to reach the gate on time, utilizing the given variables and delayed minutes. The correct expression should effectively incorporate the dog’s speed and the delay (5 minutes).
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