LAN are supplementary Prove: ZMKL ZLKN L

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Question

Please answer with explanations for proofs

Section 19 Question 7

Section 28 Questions 4 & 7

Section 30 Questions 3 & 4

Complete the proofs below by filling in the missing statements and reasons.
19. Given: 21 and 22 form a linear pair, 41 = 23
Prove: 22 and 23 are supplementary
Statements
1. 21 and 22 form a linear pair
2. 41 and 22 are supplementary
3. m21+m42 = 180°
4. 21 = 23
5. m21=mZ3
6. m23 + m2 = 180°
7. 22 and 23 are supplementary
28. Given: AB = CD; CE = AE
Prove: ED EB
Statements
1. AB = CD; CE = AE
2. AB= CD; CE = AE
3. AE+ EB = AB; CE + ED = CD
4. CE+EB= CD
5. CE+ED = CE + EB
6. ED= EB
7. ED = EB
30. Given: LJKM and ZMKL form a linear pair;
LJKM and ZLKN are supplementary
Prove: ZMKL ZLKN
Statements
1. ZJKM and ZMKL form a linear pair
2. LJKM and ZMKL are supplementary
LJKM and ZLKN are supplementary 3.
LMKL LLKN
4.
7.
Reasons
1. Given
2. Supplement Theorem
3. Definition of Supplementary Angles
7.
4. Given
5. Definition of Congruence
6.
Substitution Property
1.
Given
2. Given
Reasons
4.
5. Addition Property
6.
1. Given
2. Definition of Congruence
3.
Segment Addition Postulate
Subtraction Property
Reasons
K
3
C
N
M
Ť
E
D
B
Transcribed Image Text:Complete the proofs below by filling in the missing statements and reasons. 19. Given: 21 and 22 form a linear pair, 41 = 23 Prove: 22 and 23 are supplementary Statements 1. 21 and 22 form a linear pair 2. 41 and 22 are supplementary 3. m21+m42 = 180° 4. 21 = 23 5. m21=mZ3 6. m23 + m2 = 180° 7. 22 and 23 are supplementary 28. Given: AB = CD; CE = AE Prove: ED EB Statements 1. AB = CD; CE = AE 2. AB= CD; CE = AE 3. AE+ EB = AB; CE + ED = CD 4. CE+EB= CD 5. CE+ED = CE + EB 6. ED= EB 7. ED = EB 30. Given: LJKM and ZMKL form a linear pair; LJKM and ZLKN are supplementary Prove: ZMKL ZLKN Statements 1. ZJKM and ZMKL form a linear pair 2. LJKM and ZMKL are supplementary LJKM and ZLKN are supplementary 3. LMKL LLKN 4. 7. Reasons 1. Given 2. Supplement Theorem 3. Definition of Supplementary Angles 7. 4. Given 5. Definition of Congruence 6. Substitution Property 1. Given 2. Given Reasons 4. 5. Addition Property 6. 1. Given 2. Definition of Congruence 3. Segment Addition Postulate Subtraction Property Reasons K 3 C N M Ť E D B
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