Lalculate the pH at the halfway point and at the equivalence point for each of the following titrations a. 100.0 ml. of 0.30 M HC;H,O2 (K. = 6.4 x 10) titrated by 0.10 M NaOH pH at the halfway point pH at the equivalence point %3D b. 100.0 mL of 0.30 M C2H5 NH2 (K = 5.6 x 10 10) titrated by 0.50 M HNO3 %3D pH at the halfway point pH at the equivalence point !3! c. 100.0 mL of 0.80 M HCl titrated by 0.25 M NAOH pH at the halfway point pH at the equivalence point !!

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the pH at the halfway point and at the equivalence point for each of the following titrations.
a 100.0 mL of 0.30M HC,H,O2 (K. = 6.4 x 10) titrated by 0.10 M NaOH
%3D
pH at the halfway point=
%3D
pH at the equivalence point
b. 100.0 ml. of 0.30 M C2H; NH, (K, = 5.6 x 10) titrated by 0.50 M HNO,
%3D
pH at the halfway point =
pH at the equivalence point
c. 100.0 mL of 0.80 M HCl titrated by 0.25 M NaOH
pH at the halfway point=
pH at the equivalence point
%3D
Transcribed Image Text:[Review Topics] Calculate the pH at the halfway point and at the equivalence point for each of the following titrations. a 100.0 mL of 0.30M HC,H,O2 (K. = 6.4 x 10) titrated by 0.10 M NaOH %3D pH at the halfway point= %3D pH at the equivalence point b. 100.0 ml. of 0.30 M C2H; NH, (K, = 5.6 x 10) titrated by 0.50 M HNO, %3D pH at the halfway point = pH at the equivalence point c. 100.0 mL of 0.80 M HCl titrated by 0.25 M NaOH pH at the halfway point= pH at the equivalence point %3D
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