Lagrange's polynomial p1 (x) that interpolates f(x) = at æ = 2 and æ = 1 isSelect one:Oa. P(x) = 0.25극 +I-21-2Ob. pi(z) =D극 + 0.25는을.+ 0.25²–22-11-2O c. p1(2) = 0.25+2-I2-11-2O d. p1(x)= + 0.25.2-12-1I-2I-2I-1I-2O f. P1(x) = 0.25-11-22-1

To find the Lagrange's Interpolation p1 that interpolates the below function at x = 2 and x = 1 is,

Lagrange's polynomial p1 (x) that interpolates f(x) = at æ = 2 and x = 1 is Select one: O a. p1(a) = 0.25 + I-2 O b. p1(x) = +0.25 . I-2 O c. pi(x) = 0.25 + O d. p1(#) = + 0.25. 2–1 O e. pi(z) = 0.25 금 + . I-2 I-1

Lagrange's polynomial p1 (x) that interpolates f(x) = at æ = 2 and x = 1 is Select one: O a. p1(a) = 0.25 + I-2 O b. p1(x) = +0.25 . I-2 O c. pi(x) = 0.25 + O d. p1(#) = + 0.25. 2–1 O e. pi(z) = 0.25 금 + . I-2 I-1

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.

Question

Lagrange's polynomial p1 (x) that interpolates f(x) = at æ = 2 and æ = 1 is
Select one:
Oa. P(x) = 0.25극 +
I-2
1-2
Ob. pi(z) =D극 + 0.25는을.
+ 0.25²–2
2-1
1-2
O c. p1(2) = 0.25+
2-I
2-1
1-2
O d. p1(x)
= + 0.25.
2-1
2-1
I-2
I-2
I-1
I-2
O f. P1(x) = 0.25-1
1-2
2-1

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