Lagrange's polynomial p1 (x) that interpolates f(x) = at a = 2 and a = 5 is %3D Select one: O a. p1 (x) = 0.2 + 0.5. 2-5 O b.pi(z) = 0.5 +0.2을. = 0.51-5 5-2 2-5 Ocp(x) = 0.23 +0.5을. O d.pi(x) = 0.5플 +0.2. + 0.2프2 I-2 I-5 e. p1 (x) = 0.5 + 0.22. 2-5 O f.p: (æ) = 0.5 + 0.2. f. P1 (x) = 0.55-2 2-5 + 0.2을.

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#Numerical analysis#

Lagrange's polynomial p1 (x) that interpolates f(x) = at x = 2 and æ = 5 is
Select one:
O a. p1(x) = 0.25 + 0.52-
2-5
5-2
O b.pi(2) = 0.5을 +0.223.
I-5
O b. p1 (x)
5-2
2-5
I-2
O c. P1 (x) = 0.2 + 0.52.
2-5
d. p1 (x) = 0.5 + 0.2.
I-5
I-2
I-5
O e. p1 (1) = 0.5 + 0.2.
I-2
+ 0.2 2
5-2
O f pi(z) = 0.5 + 0.2를 .
f. p1 (x) =
5-2
5-2
Transcribed Image Text:Lagrange's polynomial p1 (x) that interpolates f(x) = at x = 2 and æ = 5 is Select one: O a. p1(x) = 0.25 + 0.52- 2-5 5-2 O b.pi(2) = 0.5을 +0.223. I-5 O b. p1 (x) 5-2 2-5 I-2 O c. P1 (x) = 0.2 + 0.52. 2-5 d. p1 (x) = 0.5 + 0.2. I-5 I-2 I-5 O e. p1 (1) = 0.5 + 0.2. I-2 + 0.2 2 5-2 O f pi(z) = 0.5 + 0.2를 . f. p1 (x) = 5-2 5-2
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