Lab Report #5-2-1: 0.1 M NaHCO3 solution, using the given pH data, calculate: [H*], [OH"]: O [H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M O [H*] = 2.2 x 10-9 M, [OH"]= 4.5 x 10-6 M %3D [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M O [H*] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M %3D
Lab Report #5-2-1: 0.1 M NaHCO3 solution, using the given pH data, calculate: [H*], [OH"]: O [H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M O [H*] = 2.2 x 10-9 M, [OH"]= 4.5 x 10-6 M %3D [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M O [H*] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![pH values
3.5
Solutions
H20 (unboiled)
H20 (boiled)
7.0
NaCl
7.0
NaC2H302
9.1
NHẠC1
4.5
NaHCO3
9.5
Na3PO4
11.9
Na2CO3
11.0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a70e2d2-d641-435a-b212-d4266cff05fc%2F1fb482c5-8a47-4e6e-b7e5-0fb578aa3c03%2Ff756ha6_processed.png&w=3840&q=75)
Transcribed Image Text:pH values
3.5
Solutions
H20 (unboiled)
H20 (boiled)
7.0
NaCl
7.0
NaC2H302
9.1
NHẠC1
4.5
NaHCO3
9.5
Na3PO4
11.9
Na2CO3
11.0
![Lab Report #5-2-1:
0.1 M NaHCO3 solution, using the given pH data, calculate: [H*], [OH¯]:
O [H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M
O [H*] = 2.2 x 10-9 M, [OH"]= 4.5 x 106 M
O [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M
O [H*] = 3.2 x 10-10 M, [OH]= 3.2 x 10-5 M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a70e2d2-d641-435a-b212-d4266cff05fc%2F1fb482c5-8a47-4e6e-b7e5-0fb578aa3c03%2Fm7rok1u_processed.png&w=3840&q=75)
Transcribed Image Text:Lab Report #5-2-1:
0.1 M NaHCO3 solution, using the given pH data, calculate: [H*], [OH¯]:
O [H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M
O [H*] = 2.2 x 10-9 M, [OH"]= 4.5 x 106 M
O [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M
O [H*] = 3.2 x 10-10 M, [OH]= 3.2 x 10-5 M
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