Lab Report #4-2-1: 0.1 M NH4CI solution, using the given pH data, calculate: [H*], [OH"]: O [H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M O [H*] = 2.2 x 10-9 M, [OH¯]= 4.5 x 10-6 M O [H*] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M %3D [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M
Lab Report #4-2-1: 0.1 M NH4CI solution, using the given pH data, calculate: [H*], [OH"]: O [H*] = 3.2 x 10-5 M, [OH"]= 3.2 x 10-10 M O [H*] = 2.2 x 10-9 M, [OH¯]= 4.5 x 10-6 M O [H*] = 3.2 x 10-10 M, [OH"]= 3.2 x 10-5 M %3D [H*] = 1.0 x 10-7 M, [OH"]= 1.0 x 10-7 M
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Lab Report #4-2-1:**
**Task:** Using a 0.1 M NH₄Cl solution and the given pH data, calculate the concentration of \([H^+]\) and \([OH^-]\).
**Options:**
- ⃝ \([H^+]\) = \(3.2 \times 10^{-5}\) M, \([OH^-]\) = \(3.2 \times 10^{-10}\) M
- ⃝ \([H^+]\) = \(2.2 \times 10^{-9}\) M, \([OH^-]\) = \(4.5 \times 10^{-6}\) M
- ⃝ \([H^+]\) = \(3.2 \times 10^{-10}\) M, \([OH^-]\) = \(3.2 \times 10^{-5}\) M
- ⃝ \([H^+]\) = \(1.0 \times 10^{-7}\) M, \([OH^-]\) = \(1.0 \times 10^{-7}\) M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6a70e2d2-d641-435a-b212-d4266cff05fc%2F0f4e02ae-fd47-447f-b4c6-c5a1fb6e012e%2Fk5gj18_processed.png&w=3840&q=75)
Transcribed Image Text:**Lab Report #4-2-1:**
**Task:** Using a 0.1 M NH₄Cl solution and the given pH data, calculate the concentration of \([H^+]\) and \([OH^-]\).
**Options:**
- ⃝ \([H^+]\) = \(3.2 \times 10^{-5}\) M, \([OH^-]\) = \(3.2 \times 10^{-10}\) M
- ⃝ \([H^+]\) = \(2.2 \times 10^{-9}\) M, \([OH^-]\) = \(4.5 \times 10^{-6}\) M
- ⃝ \([H^+]\) = \(3.2 \times 10^{-10}\) M, \([OH^-]\) = \(3.2 \times 10^{-5}\) M
- ⃝ \([H^+]\) = \(1.0 \times 10^{-7}\) M, \([OH^-]\) = \(1.0 \times 10^{-7}\) M

Transcribed Image Text:### Table of pH Values for Various Solutions
The following table presents the pH values of different solutions, both before and after specific treatments such as boiling.
| Solutions | pH Values |
|-------------------|-----------|
| H₂O (unboiled) | 3.5 |
| H₂O (boiled) | 7.0 |
| NaCl | 7.0 |
| NaC₂H₃O₂ | 9.1 |
| NH₄Cl | 4.5 |
| NaHCO₃ | 9.5 |
| Na₃PO₄ | 11.9 |
| Na₂CO₃ | 11.0 |
#### Explanation of the Table:
- **H₂O (unboiled)**: This is water that has not undergone the boiling process, with a pH of 3.5, indicating it is slightly acidic.
- **H₂O (boiled)**: Water that has been boiled shows a neutral pH of 7.0.
- **NaCl (Sodium Chloride)**: This solution has a neutral pH of 7.0.
- **NaC₂H₃O₂ (Sodium Acetate)**: This solution is slightly basic with a pH of 9.1.
- **NH₄Cl (Ammonium Chloride)**: This solution has a pH of 4.5, showing it is mildly acidic.
- **NaHCO₃ (Sodium Bicarbonate)**: This solution has a basic pH of 9.5.
- **Na₃PO₄ (Trisodium Phosphate)**: This solution is strongly basic with a pH of 11.9.
- **Na₂CO₃ (Sodium Carbonate)**: This solution also shows a strong basicity with a pH of 11.0.
Use this table to understand the acidity or basicity of common solutions, which is critical in various applications, including industrial processes, cooking, and scientific research.
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