LAB: Hailstone sequence (EO)
In Java please
6.20 LAB: Hailstone sequence (EO)
Given a positive integer num, the following rules will always create a sequence that ends with 1, called the hailstone sequence:
- If num is even, divide it by 2
- If num is odd, multiply it by 3 and add 1 (i.e. 3*num +1)
- Continue until num is 1
Write a method, hailstone(), that takes in a positive integer as a parameter and prints the hailstone sequence starting with that integer. Format the output so that ten integers, each separated by a tab character (\t), are printed per line. Assume the input to the program is always positive.
The output format can be achieved as follows:
System.out.print(num + "\t");
Ex: If the program input is:
25the output of method hailstone() is:
25 76 38 19 58 29 88 44 22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1Note: Your program must define the method:
public int hailstone(int num)
import java.util.Scanner;
public class Hailstone {
public static void hailstone(int num){
int i = 1;
while(num>0){
if(num%2==0){
System.out.print(num + "\t");
num = num / 2;
}
else {
System.out.print(num + "\t");
num = num * 3 + 1;
}
if(i==10){
i = 1;
System.out.print("");
}
else i++;
if(num==1){
System.out.println("1");
break;
}
}
}
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
Hailstone labObject = new Hailstone();
int num;
num = scnr.nextInt();
labObject.hailstone(num); // Call hailstone() to print out the hailstone sequence.
}
}
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