L000 kg of calcium phosphate is made to react with 10% excess silica, SiOz and 90% excess carbon to produce L00 kg of phosphorous. The other products are calcium silicate and carbon dioxide. ) What is the degree of completion of the reaction? ANSWER: Degree of completion = 50.08% ) illustrate the Law of Conservation of Mass. ANSWER: kg entering = kg leaving = 1387.3075 kg

L000 kg of calcium phosphate is made to react with 10% excess silica, SiOz and 90% excess carbon to produce L00 kg of phosphorous. The other products are calcium silicate and carbon dioxide. ) What is the degree of completion of the reaction? ANSWER: Degree of completion = 50.08% ) illustrate the Law of Conservation of Mass. ANSWER: kg entering = kg leaving = 1387.3075 kg

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

150 moles of A reacts with 200 moles of B via the reaction 4A+B -3C+4D The conversion of the limiting reactant is 60% f 1- Which reactant is the limiting? 2- What is the output number of moles of D?
Please type answer note write by hend
The reaction for the oxidation of NH3 is given as: 4 NH3 + 5 024 NO + 6H₂O Under certain conditions the reaction will proceed at 29.8% yield of NO. How many grams of NH3 must be used to react with excess oxygen to yield 70.5 g of NO? Hint: 70.5 g of NO is the actual yield. 21.0 134 237 2.37 None of these responses apply.
The empirical formula of an oxide
The nitrogen content of organic compounds can be determined by the Dumas method.The compound in question is first passed over hot CuO(s): Compound N2(g) + CO2(g) + H2O(g) The gaseous products are then passed through a concentrated aqueous KOH solution to remove the CO2.The remaining gas contains N2 and water vapor.A 0.127-g sample of a compound was treated as above, producing 89.0 mL of N2 saturated with water vapor at 25 °C and 739.3 torr.What is the mass percent of nitrogen in the compound? . The vapor pressure of water at 25 °C is 23.8 torr.
Given the following balanced reaction ... MnO2 + 2 KI + 2 H2SO4 → MnSO4 + K2SO4 + 2 H2O + I2 13.6 grams of KI (MW = 165.91 g/mol) and 8.57 g of MnO2 (MW = 86.94 g/mol) are reacted with excess H2SO4. Which is the limiting reagent?
1) Given the reaction: Al +_ Cuso, _Al,(SO.) Cu a) Balance the equation b) Explain why the equation represents a chemical change c) Identify the type of chemical reaction represented by the equation d) Determine the mass of Al used to react with 20 g of CUS04 to produce 15 g of Al2(SO4)3 and 25 g CU. Show work
total weight % Fe (in the ore) ive also added the formula just in case
Give typed full explanation After heating 1.1929g CaCO3 and MgCO3 for some minutes the mass of the mixture decreased to 0.8015. The %comp of CaCO3 turned out to be 54.29% and MgCO3 %comp is 45.71%. Calculate the percent error/percent yield.
Antimony is produced by heating powdered antimony trisulphide with iron and removing the molten antimony from the reaction vessel. If 1.8 kg of antimony trisulphide and 1.3 kg of iron are heated to give 0.9 kg of antimony. The reaction is as follows: Sb2S3 + 3Fe --> 2Sb + 3FeS The amount of percentage excess of the Excess Reactant is: The amount of percentage excess of the Excess Reactant is: 46.45% 52.77% 47.53% 69.75% The degree of completion of the reaction is: 46.45% 52.77% 47.53% 69.75% The percentage conversion of iron is: 46.45% 52.77% 47.53% 69.75%
11. How much iron, in kg, would need to be used in excess oxygen to produce 1,679 g of rust (iron(III) oxide)? use dimensional analysis to complete this question
STARTING AMOUNT + Consider the Haber-Bosch process for the synthesis of ammonia from its elements. Calculate the theoretical yield in moles NH from the complete reaction of 15.6 grams H₂ in the presence of excess N2 gas according to the following balanced chemical equation: ADD FACTOR * ( ) N2(g) + 3 H2(g) → 2 |NH,(9) = ANSWER RESET ១ 11.6 28.02 5.15 197 2.02 17.04 2.57 10.3 1.01 7.72 14.01 0.612 1 2 15.6 0.306 3 0.918 87.7 mol H₂ g/mol NH g/mol H₂ g NH3 mol NH g H₂