L0.2.35 lim tan- 7n = 10.2.36 Note that el/10 = 19e 1.1. Let r = el/10 en/10 and note that 0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question

My question is , why does this equal 0? I thought the limit was infinity here. ? Because  (e^1/10/2)^n I thought was infinity?

**Section 10.2: Limits and Exponentials**

**Problem 10.2.35:**
Find the limit:

\[
\lim_{{n \to \infty}} \tan^{-1} n = \frac{\pi}{2}
\]

**Problem 10.2.36:**
Consider the expression:

\[ e^{1/10} = \sqrt[10]{e} \approx 1.1. \]

Let \( r = \frac{e^{1/10}}{2} \) and note that \( 0 < r < 1 \).

Therefore, 

\[
\lim_{{n \to \infty}} \frac{e^{n/10}}{2^n} = \lim_{{n \to \infty}} r^n = 0.
\] 

This demonstrates how exponential limits can converge to zero when the base of the exponential is less than 1.
Transcribed Image Text:**Section 10.2: Limits and Exponentials** **Problem 10.2.35:** Find the limit: \[ \lim_{{n \to \infty}} \tan^{-1} n = \frac{\pi}{2} \] **Problem 10.2.36:** Consider the expression: \[ e^{1/10} = \sqrt[10]{e} \approx 1.1. \] Let \( r = \frac{e^{1/10}}{2} \) and note that \( 0 < r < 1 \). Therefore, \[ \lim_{{n \to \infty}} \frac{e^{n/10}}{2^n} = \lim_{{n \to \infty}} r^n = 0. \] This demonstrates how exponential limits can converge to zero when the base of the exponential is less than 1.
Certainly! Here is the transcription and explanation suitable for an educational website:

---

**Question 36:**

Evaluate the expression:

\[
\left\{ \frac{e^{n/10}}{2^n} \right\}
\]

**Explanation:**

This problem involves an exponential function where \( e^{n/10} \) is divided by \( 2^n \). The curly braces suggest that you may need to find the fractional part of the expression for different values of \( n \).

**Steps to Consider:**

1. **Understand the Function:**
   - **Numerator:** \( e^{n/10} \) – An exponential function where \( n \) is divided by 10.
   - **Denominator:** \( 2^n \) – An exponential function with base 2 raised to the power \( n \).

2. **Evaluate for sample values of \( n \):**
   - Substitute specific values for \( n \) to determine the behavior of the function.
   - Calculate the result and extract the fractional part.

3. **Graphical Representation (if required):**
   - A graph of \( \frac{e^{n/10}}{2^n} \) versus \( n \) may illustrate the convergence behavior or how the fractional part changes.

Use this as a guideline to explore the function further and recognize patterns that emerge with different \( n \) values.

---
Transcribed Image Text:Certainly! Here is the transcription and explanation suitable for an educational website: --- **Question 36:** Evaluate the expression: \[ \left\{ \frac{e^{n/10}}{2^n} \right\} \] **Explanation:** This problem involves an exponential function where \( e^{n/10} \) is divided by \( 2^n \). The curly braces suggest that you may need to find the fractional part of the expression for different values of \( n \). **Steps to Consider:** 1. **Understand the Function:** - **Numerator:** \( e^{n/10} \) – An exponential function where \( n \) is divided by 10. - **Denominator:** \( 2^n \) – An exponential function with base 2 raised to the power \( n \). 2. **Evaluate for sample values of \( n \):** - Substitute specific values for \( n \) to determine the behavior of the function. - Calculate the result and extract the fractional part. 3. **Graphical Representation (if required):** - A graph of \( \frac{e^{n/10}}{2^n} \) versus \( n \) may illustrate the convergence behavior or how the fractional part changes. Use this as a guideline to explore the function further and recognize patterns that emerge with different \( n \) values. ---
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning