L.² [² (6xyz + 32²) dz dy dz

Q: In the Taylor series expansion of exp(x) + sin (x) about the point x = T, the coefficient of (x- T)2…

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Q: .3 1 J2 dx=? x² – 4x+5

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Q: 4. √ √x(2x-¹ – 1)¹/² dx

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Q: +). L x-1 dx -1x2+1

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Q: Evaluate dx. /25 – x²

A: First of all, let x = 5 sin (u) and differentiate w.r.t x on both sides of the equation and find dx.

Q: Evaluate L L ³ xy² 1 3xy² dy dx.

A: SOLUTION-

Q: 3. LLa (x + 2y) dy dx

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Q: .2 dx Jo (9 + x²)2

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Q: 22 Evaluate S- dx. 3/2 +1

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Q: (1+4xy) dx dy O a. 10 O b. 9 O c. 7 O d. 8

A: To evaluate the given double integral.

Q: .2 dx 6. (x-1)3

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Q: 1- S dx -4 4

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Q: 2 4, X – 4x xP c(7

A: Solution:-     Given        ∫03/2 x4 9-4x25  dx.

Q: dx Evaluate • (1–2x)² 0 1 1 2 O-1 o 1 2

A: We have ∫-∞0dx(1-2x)2

Q: 1 8.) d.x (x2 + 16)3/2

A: We have to find

Q: Part. d. True or False: d 1 dx 3 X 1 2 3x

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Q: 4. (x? — у?)dx — 2хydy %3D 0

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Q: 1. 2 sec" (8x -) d n) dx

A: to evaluate the integration of 2sec^2(8x-π/4)

Q: 1. [²+3x - 4)dx

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Q: Find. (x²+1)3 2x dx

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Q: 1. Find dx. x2 + 64

A: I = ∫1x2x2 + 64 dxLet x = 8 tanθ     dx = 8 sec2 θ dθx2 + 64 = 64 tan2θ + 64                 = 64…

Q: + wha x+8'

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Q: 8 .3 X (1+x)5 - dx

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Q: SIT x y z dx dy dz Evaluate 0. O 3 0 4 0 1 O 2

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Q: 2. Evaluate 4 dx . 2 x²- 36 -00

A: