Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations: Compute L, and the elevations at the full
Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations: Compute L, and the elevations at the full
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Field conditions require a highway curve to pass through a fixed point. Compute a suitable equal-tangent vertical curve and full-station elevations: Compute L, and the elevations at the full stations)
Grades of g1 = −2.50% and g2 = +1.50%, VPI elevation 2560.00 ft at station 315 + 00 Fixed elevation 2567.00 ft at station 314 + 00.
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L = 1268.46 ft
2567 = 2560 + 2.5(L/2) − 2.5(L/2 − 1) + (1.5 + 2.5)/(2L) (L/2 − 1)2 L2 −13L+4=0
BVC Station = 308+65.77BVC Elevation = 2575.8
Minimum elevation = 2,565.95 @ station 316+58.56.
This is what the textbook lists, I just wasn't sure how L was calculated and how the values in the table were calculated.
Transcribed Image Text:Station
321+34.23
321+00.00
320+00.00
319+00.00
318+00.00
317+00.00
316+00.00
315+00.00
314+00.00
313+00.00
312+00.00
311+00.00
310+00.00
309+00.00
308+65.77
x (Sta)
12.68
12.34
11.34
10.34
9.34
8.34
7.34
6.34
5.34
4.34
3.34
2.34
1.34
0.34
0
gl*x
-31.71
-30.86
-28.36
-25.86
-23.36
-20.86
-18.36
-15.86
-13.36
-10.86
-8.36
-5.86
-3.36
-0.86
0
r/2*x*x
25.37
24.02
20.28
16.87
13.76
10.97
8.50
6.34
4.50
2.97
1.76
0.87
0.28
0.02
0
Elevation
2,569.51
2,569.02
2,567.78
2,566.87
2,566.26
2,565.97
2,566.00
2,566.34
2,567.00
2,567.97
2,569.26
2,570.87
2,572.78
2,575.02
2,575.86
===
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