Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Can u help me solve this, please explain the step too so I can understand it thanks!
![The image contains a mathematical expression written on lined paper. The expression is:
\[
\frac{k}{k+1} + \frac{1}{(k+1) \times (k+2)}
\]
This expression consists of two fractions.
- The first fraction is \( \frac{k}{k+1} \), where \( k \) is the numerator and \( k+1 \) is the denominator.
- The second fraction is \( \frac{1}{(k+1) \times (k+2)} \), where 1 is the numerator and the denominator is the product of \( (k+1) \) and \( (k+2) \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4d6e69c4-d052-4f2e-8ec9-6856675877b5%2F130db351-5125-4765-a4a0-3fd20ce5498e%2Faanqdxq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The image contains a mathematical expression written on lined paper. The expression is:
\[
\frac{k}{k+1} + \frac{1}{(k+1) \times (k+2)}
\]
This expression consists of two fractions.
- The first fraction is \( \frac{k}{k+1} \), where \( k \) is the numerator and \( k+1 \) is the denominator.
- The second fraction is \( \frac{1}{(k+1) \times (k+2)} \), where 1 is the numerator and the denominator is the product of \( (k+1) \) and \( (k+2) \).
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