K(r)= er tre k' = d (e^) + d dr " er + dr - (re) Help with this derivative

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I am stuck on this derivative.
### Calculating the Derivative of a Function

**Function Definition:**
\[ K(r) = e^r + r e \]

**Derivative Calculation:**
To find \( K'(r) \), we need to differentiate each term of the function \( K(r) \) with respect to \( r \).

\[ K' = \frac{d}{dr} ( e^r ) + \frac{d}{dr} ( r e ) \]

**First Term:**
The derivative of \( e^r \) with respect to \( r \):

\[ \frac{d}{dr} ( e^r ) = e^r \]

**Second Term:**
The derivative of \( r e \) with respect to \( r \):

The term \( r e \) is highlighted and it seems there is a request for help with computing this derivative. Let's break it down:
- Recognize that \( e \) is a constant with respect to \( r \).
- The derivative of \( r \) (a linear term) is \( 1 \).

\[ \frac{d}{dr} ( r e ) = e \]

Therefore, summing the derivatives of each term:

\[ K'(r) = e^r + e \]

**Note:**
There was a handwritten note requesting help with the highlighted derivative part \( \frac{d}{dr} (r e) \). From the context, it's clear that understanding constants when differentiating is key here. Since \( e \) is a constant, the differential simplifies straightforwardly.
Transcribed Image Text:### Calculating the Derivative of a Function **Function Definition:** \[ K(r) = e^r + r e \] **Derivative Calculation:** To find \( K'(r) \), we need to differentiate each term of the function \( K(r) \) with respect to \( r \). \[ K' = \frac{d}{dr} ( e^r ) + \frac{d}{dr} ( r e ) \] **First Term:** The derivative of \( e^r \) with respect to \( r \): \[ \frac{d}{dr} ( e^r ) = e^r \] **Second Term:** The derivative of \( r e \) with respect to \( r \): The term \( r e \) is highlighted and it seems there is a request for help with computing this derivative. Let's break it down: - Recognize that \( e \) is a constant with respect to \( r \). - The derivative of \( r \) (a linear term) is \( 1 \). \[ \frac{d}{dr} ( r e ) = e \] Therefore, summing the derivatives of each term: \[ K'(r) = e^r + e \] **Note:** There was a handwritten note requesting help with the highlighted derivative part \( \frac{d}{dr} (r e) \). From the context, it's clear that understanding constants when differentiating is key here. Since \( e \) is a constant, the differential simplifies straightforwardly.
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