Knowledge/Understanding Multiple Choice: 1. Determine a b given thatā = (2, -7) and b = (-3,6) a) -36 b) -48 2. 3(2-3)-2(-5) -4v simplified is: a) 16u-15 b) 4u-3v 3. The function whose graph has a slant (oblique) asymptote is: 6x2 a) y= x3+5x b) y= x4-8x+9 x4+5 4. The derivative of y = sin(7x-4) is: a) 7cos(7x-4) b) -7cos(7x-4) 5. The conjugate of 2√√7 - √√3 is: a) √3-2√7 b) -2√√7+ √√3 c) 48 d) 36 c)-3-6v d) 16-11 c) y = x4-2 x3+x²-1 d) b and c c) cos(7x-4) d) (7x-4)cos(7x-4) c) √7 + √3 6. In R³, the standard basis (unit) vector, & can be expressed in component form as: a) (1, 0, 0) b) (0, 1, 0) c) (0, 0, 1) 7. Evaluate the following limits: lim√√4+ √√25+x d) 2√√7+ √√3 d) (1, 1, 1) a) 2+√√5 x-0 b) 3 c) ±3 d) 7 b) a × b=b× ā c) a⋅ b = ba d) a − b = − b + a 8. The incorrect vector property is: a) a + b = b + ã 9. If a vector is described as an airplane flying North at 400km/h, then the opposite vector can be described as: a) An airplane flying North at -400km/h c) An airplane flying South at 800km/h b) An airplane flying South at 400km/h d) Both b and c 10. For u and v, if the sign of u vis negative, then the angle between the tail to tail vectors will be: a)0
Knowledge/Understanding Multiple Choice: 1. Determine a b given thatā = (2, -7) and b = (-3,6) a) -36 b) -48 2. 3(2-3)-2(-5) -4v simplified is: a) 16u-15 b) 4u-3v 3. The function whose graph has a slant (oblique) asymptote is: 6x2 a) y= x3+5x b) y= x4-8x+9 x4+5 4. The derivative of y = sin(7x-4) is: a) 7cos(7x-4) b) -7cos(7x-4) 5. The conjugate of 2√√7 - √√3 is: a) √3-2√7 b) -2√√7+ √√3 c) 48 d) 36 c)-3-6v d) 16-11 c) y = x4-2 x3+x²-1 d) b and c c) cos(7x-4) d) (7x-4)cos(7x-4) c) √7 + √3 6. In R³, the standard basis (unit) vector, & can be expressed in component form as: a) (1, 0, 0) b) (0, 1, 0) c) (0, 0, 1) 7. Evaluate the following limits: lim√√4+ √√25+x d) 2√√7+ √√3 d) (1, 1, 1) a) 2+√√5 x-0 b) 3 c) ±3 d) 7 b) a × b=b× ā c) a⋅ b = ba d) a − b = − b + a 8. The incorrect vector property is: a) a + b = b + ã 9. If a vector is described as an airplane flying North at 400km/h, then the opposite vector can be described as: a) An airplane flying North at -400km/h c) An airplane flying South at 800km/h b) An airplane flying South at 400km/h d) Both b and c 10. For u and v, if the sign of u vis negative, then the angle between the tail to tail vectors will be: a)0
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Transcribed Image Text:Knowledge/Understanding
Multiple Choice:
1. Determine a b given thatā = (2, -7) and b = (-3,6)
a) -36
b) -48
2. 3(2-3)-2(-5) -4v simplified is:
a) 16u-15
b) 4u-3v
3. The function whose graph has a slant (oblique) asymptote is:
6x2
a) y=
x3+5x
b) y=
x4-8x+9
x4+5
4. The derivative of y = sin(7x-4) is:
a) 7cos(7x-4)
b) -7cos(7x-4)
5. The conjugate of 2√√7 - √√3 is:
a) √3-2√7
b) -2√√7+ √√3
c) 48
d) 36
c)-3-6v
d) 16-11
c) y =
x4-2
x3+x²-1
d) b and c
c) cos(7x-4)
d) (7x-4)cos(7x-4)
c) √7 + √3
6. In R³, the standard basis (unit) vector, & can be expressed in component form as:
a) (1, 0, 0)
b) (0, 1, 0)
c) (0, 0, 1)
7. Evaluate the following limits: lim√√4+ √√25+x
d) 2√√7+ √√3
d) (1, 1, 1)
a) 2+√√5
x-0
b) 3
c) ±3
d) 7
b) a × b=b× ā
c) a⋅ b = ba
d) a − b = − b + a
8. The incorrect vector property is:
a) a + b = b + ã
9. If a vector is described as an airplane flying North at 400km/h, then the opposite vector can be described
as:
a) An airplane flying North at -400km/h
c) An airplane flying South at 800km/h
b) An airplane flying South at 400km/h
d) Both b and c
10. For u and v, if the sign of u vis negative, then the angle between the tail to tail vectors will be:
a)0<e<900
c) 90° <D<1800
d) Sign does not indicate angle range
b)O =900
11. Evaluate the following limit: lim
9-x2
x-3 3-x
a) Undefined
b) 3
c) 6
12. Determine the slope of the tangent to the curve y = 2sinx + sin²x when x
a)
b) 0
c)
2
d) 0
d)
3+4√3
4
![13. Find the torque produced by a cyclist exerting a force of F = [45, 90, 130]N on the shaft- pedal
d = [12, 17, 14] cm long.
a) (-950, 930, -315)
b) 3890
c) 19874
14. Given a = [3,−1,4]& c = [−2, 6, t], find t so that a and c are perpendicular.
a) 4
b) -3
c) -4
d) 1866625
d) 3
15. Given = [-12, 6, k]&v = [4,-2, 4], find k so that u and v are parallel.
a) 4
b) -3
c) 6
d) -12
16. An object moves along a straight line in such a way that its position is s(t) = −5t³ + 17t², in which t
represents the time in seconds. What is the object's acceleration at 2.7 seconds?
a) -47
b) -17.55
17. Find the unit vector of a = [-3, -7,4].
c) 17
d) -81
a) -3, -7,4]
b) -3,-7,4]
4
d)
[√74 74 √]
18. Derive y = -2(3-7)
a) -21n3(3-7x)
b) -14ln7(3-7x)
c) 7ln2(3-7x)
d) 14ln3(3-7x)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F633dc666-1c4e-4222-82a0-1d910c7662c5%2Ffbd07f2a-cd26-4463-bdd1-2764f460c168%2F2yov3m_processed.png&w=3840&q=75)
Transcribed Image Text:13. Find the torque produced by a cyclist exerting a force of F = [45, 90, 130]N on the shaft- pedal
d = [12, 17, 14] cm long.
a) (-950, 930, -315)
b) 3890
c) 19874
14. Given a = [3,−1,4]& c = [−2, 6, t], find t so that a and c are perpendicular.
a) 4
b) -3
c) -4
d) 1866625
d) 3
15. Given = [-12, 6, k]&v = [4,-2, 4], find k so that u and v are parallel.
a) 4
b) -3
c) 6
d) -12
16. An object moves along a straight line in such a way that its position is s(t) = −5t³ + 17t², in which t
represents the time in seconds. What is the object's acceleration at 2.7 seconds?
a) -47
b) -17.55
17. Find the unit vector of a = [-3, -7,4].
c) 17
d) -81
a) -3, -7,4]
b) -3,-7,4]
4
d)
[√74 74 √]
18. Derive y = -2(3-7)
a) -21n3(3-7x)
b) -14ln7(3-7x)
c) 7ln2(3-7x)
d) 14ln3(3-7x)
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