Knowing that the tension in cable BC is 725N, determine the resultant of the three forces exerted at point B of beam AB. -840mm L- 1160mm 800mm B 13 5 12 780 N 500 N
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A: Concept used: Cosine components of force act only x-axis. Sine components of force act along y-axis.
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A: F1 = 24.3 N, a = 12.2 ms2 θ = 33.0°mass of the block, m = 2.71 kg
Q: Q7- Determine the angle between the arm BA and forearm BC
A: Given : BA→ = 6i+18j-10kBC→ = -12i+35j+20k-6i+18j-10k= -18i+17j+30k
Q: Rearange to find g T^2=4pi^2(1/g)
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- Needs Complete typed solution with 100 % accuracy.A 1.70 m bar moves through a uniform, 1.70 T magnetic field with a speed of 2.00 m/s. Figure R V X 1 of 3 Part A For (Figure 1), find the emf induced between the ends of the bar. Express your answer in volts. 17 ΑΣΦ ε = Submit Part B Which end of this bar, if either, is at the higher potential? none OR L Submit Part C E = Submit Part D For (Figure 2), find the emf induced between the ends of the bar. Express your answer in volts. VE ΑΣΦ. Request Answer none OL OR Request Answer Which end of this bar, if either, is at the higher potential? Submit Request Answer ? Request Answer V ? Vi should have said where; p=V^2/R P=[ML^2 T^-3] V=[L^0.5 M^0.5 T^-1] solve for R
- In an examination of a pediatric patient the operating console controls are set at 600 mA/30 ms. Whatis the mAs?Assume e = 25.2 what is T if objcct is In static equilibrym? %3D A4PreLab Equilibrium questions: 1) In Figure1 in manual F1 = 185.0gm-wt, F2 = 205gm-wt, 01 = 35.0 degrees and 02 = 56.0 degrees. a) Determine magnitude and direction of F3. %3D 2) In figures 3 and 4, AM = 14.4cm, F2 = 165gm-wt and 02= 56.0 degrees. Calculate Torque of F2 about the point A and sense of rotation. %3D 3) In figures 3 and 4, AN = 13.4cm, F3 = 75gm-wt and 03 = 79.0 degrees. Calculate Torque of F3 about the point A and sense of rotation. %3D