**Problem Statement:**Knowing that the radius of each pulley is 200 mm, \( P = 440 \, \text{N} \), and neglecting friction, determine the internal forces at point \( J \) of the frame shown. (Round the magnitudes to the nearest whole number and the angles to one decimal place.)**Diagram Explanation:**The diagram illustrates a mechanical system featuring a frame with pulleys. Key components and dimensions are labeled:- The frame adheres to a vertical wall at point \( B \).- Points \( A, B, C, D, E, \) and \( J \) are marked on the frame.- Pulley connections are visible at points \( C \) and \( E \) with a force \( P \) acting vertically downward at \( E \).- Dimensions include a vertical distance of 1.8 m from \( B \) to \( D \), and horizontal segments of length 0.8 m from \( E \) to \( K \) and from \( K \) to \( D \), with an additional 0.2 m from \( E \) along a vertical line.**Calculations:**- The axial force \( F \) is \( 244.483 \, \text{N} \), directed at an angle of \( 37^\circ \).- The shear force \( V \) is \( -146.66 \, \text{N} \), acting at an angle of \( 53^\circ \).- The bending moment \( M \) is \( 146.668 \, \text{N} \cdot \text{m} \), in the counter-clockwise direction.Ensure to visualize how forces are applied within the frame, considering the given constraints and dimensions to understand the internal force distribution thoroughly.

Answered: Image /qna-images/answer/cac32022-94d2-480b-bb48-5eb62a551171.jpg

Knowing that the radius of each pulley is 200 mm, P= 440 N, and neglecting friction, determine the internal forces at point J of the frame shown. (Round the magnitudes to the nearest whole number and the angles to one decimal place.) 1.8 m B A D 0.8 m K 0.8 m E| 0.8 m The axial force Fis 244.483 N The shear force Vis -146.66 N 4 The bending moment Mis 146.668 -0.2 m P 37 °. 53 *°. N-m in the counter-clockwise direction

Knowing that the radius of each pulley is 200 mm, P= 440 N, and neglecting friction, determine the internal forces at point J of the frame shown. (Round the magnitudes to the nearest whole number and the angles to one decimal place.) 1.8 m B A D 0.8 m K 0.8 m E| 0.8 m The axial force Fis 244.483 N The shear force Vis -146.66 N 4 The bending moment Mis 146.668 -0.2 m P 37 °. 53 *°. N-m in the counter-clockwise direction

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

**Problem Statement:**

Knowing that the radius of each pulley is 200 mm, \( P = 440 \, \text{N} \), and neglecting friction, determine the internal forces at point \( J \) of the frame shown. (Round the magnitudes to the nearest whole number and the angles to one decimal place.)

**Diagram Explanation:**

The diagram illustrates a mechanical system featuring a frame with pulleys. Key components and dimensions are labeled:
- The frame adheres to a vertical wall at point \( B \).
- Points \( A, B, C, D, E, \) and \( J \) are marked on the frame.
- Pulley connections are visible at points \( C \) and \( E \) with a force \( P \) acting vertically downward at \( E \).
- Dimensions include a vertical distance of 1.8 m from \( B \) to \( D \), and horizontal segments of length 0.8 m from \( E \) to \( K \) and from \( K \) to \( D \), with an additional 0.2 m from \( E \) along a vertical line.

**Calculations:**

- The axial force \( F \) is \( 244.483 \, \text{N} \), directed at an angle of \( 37^\circ \).
- The shear force \( V \) is \( -146.66 \, \text{N} \), acting at an angle of \( 53^\circ \).
- The bending moment \( M \) is \( 146.668 \, \text{N} \cdot \text{m} \), in the counter-clockwise direction.

Ensure to visualize how forces are applied within the frame, considering the given constraints and dimensions to understand the internal force distribution thoroughly.

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