Knowing that the basis for the space of solutions to the homogeneous differential equation the functions y1=1 and y2=tan(2x) determine a particular solution by the method of variation of parameters to the differential equation: -4 tan(2 x) y' + y" = sec(2 x) A Yp cos(2 x) – 4 sen(2 x) tan(2 x) B Yp = -2 cos(2 x) +2 sen(2 x) tan(2 x) C Yp = 4 cos(2 x) +4 sen(2 x) tan(2 x) %3D Yp = -4 cos(2 æ) – 4 sen(2 x) tan(2 x) E Yp = i cos(2 x) + sen(2 x) tan(2 x)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Knowing that the basis for the space of
solutions to the homogeneous differential
equation the functions y1=1 and y2=tan(2x)
determine a particular solution by the
method of variation of parameters to the
differential equation:
-4 tan(2 x) y' + y" = sec(2 x)
A
Yp
cos(2 x) – 4 sen(2 x) tan(2 x)
B
Yp = -2 cos(2 x) +2 sen(2 x) tan(2 x)
C
Yp = 4 cos(2 x) +4 sen(2 x) tan(2 x)
Yp = –4 cos(2 x) – 4 sen(2 x) tan(2 x)
E
Yp = i cos(2 x) + sen(2 x) tan(2 x)
Transcribed Image Text:Knowing that the basis for the space of solutions to the homogeneous differential equation the functions y1=1 and y2=tan(2x) determine a particular solution by the method of variation of parameters to the differential equation: -4 tan(2 x) y' + y" = sec(2 x) A Yp cos(2 x) – 4 sen(2 x) tan(2 x) B Yp = -2 cos(2 x) +2 sen(2 x) tan(2 x) C Yp = 4 cos(2 x) +4 sen(2 x) tan(2 x) Yp = –4 cos(2 x) – 4 sen(2 x) tan(2 x) E Yp = i cos(2 x) + sen(2 x) tan(2 x)
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