Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. В). Determine (a) the compressive force in the bars shown after a temperature rise of 180°F, (b) the corresponding change in length of the bronze bar. 0.02 in. -14 in. 18 in. Aluminum A = 2.8 in? E = 10.6 X 106 psi Bronze A = 2.4 in? E = 15 x 106 psi a = 12 x 10-6/°F a = 12.9 x 10-F
Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. В). Determine (a) the compressive force in the bars shown after a temperature rise of 180°F, (b) the corresponding change in length of the bronze bar. 0.02 in. -14 in. 18 in. Aluminum A = 2.8 in? E = 10.6 X 106 psi Bronze A = 2.4 in? E = 15 x 106 psi a = 12 x 10-6/°F a = 12.9 x 10-F
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Q4

Transcribed Image Text:4. Problem Statement:
A).
Knowing that a 0.02-in. gap exists when the temperature is 75°F,
determine (a) the temperature at which the normal stress in the
aluminum bar will be equal to -11 ksi, (b) the corresponding exact
length of the aluminum bar.
В).
Determine (a) the compressive force in the bars shown after a
temperature rise of 180°F, (b) the corresponding change in length
of the bronze bar.
0.02 in.
14 in.
18 in.
Bronze
Aluminum
A = 2.4 in?
E = 15 x 106 psi
a = 12 x 10-6/°F
A = 2.8 in?
E = 10.6 × 10® psi
a = 12.9 x 10-/°F
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