KNN, decision tree: (Machine learning) Please ans question B and C specifically- 6. Consider a binary classification problem using 1-nearest neighbors with the Euclidean distance metric. We have N 1-dimensional training points x(1), x(2), . . . x(N ) and corresponding labels y(1), y(2), . . . y(N ) with x(i ) ∈ R and y(i ) ∈ {0, 1}. Assume the points x(1), x(2), . . . x(N ) are in ascending order by value. If there are ties during the 1-NN algorithm, we break ties by choosing the label corresponding to the x(i ) with lower value. (a) Is it possible to build a decision tree that behaves exactly the same as the
KNN, decision tree: (Machine learning)
Please ans question B and C specifically-
6. Consider a binary classification problem using 1-nearest neighbors with the Euclidean distance metric. We have N 1-dimensional training points x(1), x(2), . . . x(N ) and corresponding labels
y(1), y(2), . . . y(N ) with x(i ) ∈ R and y(i ) ∈ {0, 1}. Assume the points x(1), x(2), . . . x(N ) are in ascending order by value. If there are ties during the 1-NN
corresponding to the x(i ) with lower value.
(a) | Is it possible to build a decision tree that behaves exactly the same as the 1-nearest neighbor classifier? Assume that the decision at each node takes the form of “ x ≤ t or |
x > t,” where t ∈R.
◯ Yes
◯ No
If your answer is yes, please explain how you will construct the decision tree. If your answer is no,
explain why it’s not possible.
(b) Let’s add a dimension! Now assume the training points are 2-dimensional
where x(i ) = ( x( 1i), x( 2i )) ∈R2 and the decision at each node takes the form of “ xj ≤ t or xj > t,”
where t ∈ R and j ∈ {1, 2}. Give an example with at most 3 training points for which it isn’t
possible to build a decision tree that behaves exactly the same as a 1-nearest neighbor classifier.
(c) Assuming we have 2-dimensional training points x(i ) = ( x( 1i ), x( 2i )) ∈R2 and
the decision at each node takes the form of “ xj ≤t or xj > t,” where t ∈ R and j ∈ {1, 2}, under
what conditions is it possible to build a decision tree that behaves exactly the same as a 1-nearest
neighbor classifier? Explain why it is possible to build the decision tree as stated in part (a) but, in
general, not possible in part (b).
![Decision tree, KNN:
Consider a binary classification problem using 1-nearest neighbors with the Euclidean dis-
and corresponding labels
6.
(2).x2). .
tance metric. We have N 1-dimensional training points x
y4, y2, ...) with xº) e R and y) e (0, 1. Assume the points x(4, x2), .
ing order by value. If there are ties during the 1-NN algorithm, we break ties by choosing the label
corresponding to the x" with lower value.
....
Is it possible to build a decision tree that behaves exactly the same as the
(a)
1-nearest neighbor classifier? Assume that the decision at each node takes the form of“ x st or
x > t," where t ER.
Yes
No
If your answer is yes, please explain how you will construct the decision tree. If your answer is no,
explain why it's not possible.
(b)
where x" = *", x") ER? and the decision at each node takes the form of “ X¡ st or Xj > t,"
where t eR and j e (1, 2. Give an example with at most 3 training points for which it isn't
possible to build a decision tree that behaves exactly the same as a 1-nearest neighbor classifier.
Let's add a dimension!
Now assume the training points are 2-dimensional
x" = *, x2) eR?:
_i)
(c)
the decision at each node takes the form of “ X¡ <t or Xj > t," where t eR andj e 1, 2, under
what conditions is it possible to build a decision tree that behaves exactly the same as a 1-nearest
neighbor classifier? Explain why it is possible to build the decision tree as stated in part (a) but, in
general, not possible in part (b).
Assuming we have 2-dimensional training points](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4832ffb9-00ea-4041-bd30-197dd3c6027e%2F593b3e16-c877-4ab6-b7b5-fbc806e294c7%2Fn26efpn_processed.png&w=3840&q=75)
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