kN, 0 = 57° 31] 20. A roller gate is shown in Fig. 3.59. It is cylindrical form of 6.0 m diameter. It is placed on the dam Fi the magnitude and direction of the resultant force due to water acting on the gate when the water is ju [Ans. 2.245 MN, 0= 38°) going to spill. The length of the gate is given 10 m. ROLLER

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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is 10 m. Each gate is supported by two hinges located at I m and 5 m above the bottom of the lock. The
gate, and (i) magnitude of the hinge reactions. [Ans. () 79.279 kN, (i) R7=27.924 kN, R-S1.3AN
depth of water on the upstream and downstream sides of the lock are 6 m and 4 m respectively. Find:
gates are closed, they make an angle of 120°. The width of the lock is 4 m. If the depths of water on the ne
sides of the gates are 4 m and 3 m respectively, determine : () the magnitude of resultant pressure on ca
() Resultant water force on cach gate.
24. The end gates ABC of a lock are 8 m high and when closed make an angle of 120°. The width of kat
19. Fig. 3.58 shows a gate having a quadrant shape of radius of 3 m. Find the resultant force due to wa
metre length of the gate. Find also the angle at which the total force will act. [Ans. 82.201 kN, 0 = 57 3n
20. A roller gate is shown in Fig. 3.59. It is cylindrical form of 6.0 m diameter. It is placed on the dam
the magnitude and direction of the resultant force due to water acting on the gate when the water is j
going to spill. The length of the gate is given 10 m.
[Ans. 2.245 MN, 8= 38*)
ROLLER
GATE
WATER SURFACE
R=4 m
6.0 m
WATER SURFACEC
307
30
HÍNGE
DAM
Fig.3.59
Fig. 3.60
21. Find the horizontal and vertical components of the water pressure exerted on a tainter gate of
4 m as shown in Fig. 3.60. Consider width of the gate unity.
[Ans. F,= 19.62 kN, F, = 71024N
22. Find the magnitude and direction of the resultant water
pressure acting on a curved face of a dam which is shaped
WATER SURFACE
acconding to the relation y=
as shown in Fig. 3.61. The
12 m:
height of water retained by the dam is 12 m. Take the width
of dam as unity.
23. Each gate of a lock is 5 m high and is supported by two
hinges placed on the top and bottom of the gate. When the
(Ans. 970.74 kN, 8 = 43° 191
Fig. 3.61
ma
Transcribed Image Text:is 10 m. Each gate is supported by two hinges located at I m and 5 m above the bottom of the lock. The gate, and (i) magnitude of the hinge reactions. [Ans. () 79.279 kN, (i) R7=27.924 kN, R-S1.3AN depth of water on the upstream and downstream sides of the lock are 6 m and 4 m respectively. Find: gates are closed, they make an angle of 120°. The width of the lock is 4 m. If the depths of water on the ne sides of the gates are 4 m and 3 m respectively, determine : () the magnitude of resultant pressure on ca () Resultant water force on cach gate. 24. The end gates ABC of a lock are 8 m high and when closed make an angle of 120°. The width of kat 19. Fig. 3.58 shows a gate having a quadrant shape of radius of 3 m. Find the resultant force due to wa metre length of the gate. Find also the angle at which the total force will act. [Ans. 82.201 kN, 0 = 57 3n 20. A roller gate is shown in Fig. 3.59. It is cylindrical form of 6.0 m diameter. It is placed on the dam the magnitude and direction of the resultant force due to water acting on the gate when the water is j going to spill. The length of the gate is given 10 m. [Ans. 2.245 MN, 8= 38*) ROLLER GATE WATER SURFACE R=4 m 6.0 m WATER SURFACEC 307 30 HÍNGE DAM Fig.3.59 Fig. 3.60 21. Find the horizontal and vertical components of the water pressure exerted on a tainter gate of 4 m as shown in Fig. 3.60. Consider width of the gate unity. [Ans. F,= 19.62 kN, F, = 71024N 22. Find the magnitude and direction of the resultant water pressure acting on a curved face of a dam which is shaped WATER SURFACE acconding to the relation y= as shown in Fig. 3.61. The 12 m: height of water retained by the dam is 12 m. Take the width of dam as unity. 23. Each gate of a lock is 5 m high and is supported by two hinges placed on the top and bottom of the gate. When the (Ans. 970.74 kN, 8 = 43° 191 Fig. 3.61 ma
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