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KLeibow = 0.3 In figure, if the velocity = 4 ft/s, K entrance 0.5 Kelbow-0.2, K exit ? 1. minor losses 9 Diameter = 0.5 ft. Elevation = 200 ft (1) KLentrance = 0.6 PUMP FORWEG -Total length of pipe = 200 ft Closed tank p = 3 psi Air (2) Elevation = 195 ft PPRONTPEERRING 1.55 ft 0.57 ft O 0.47 ft O

KLeibow = 0.3 In figure, if the velocity = 4 ft/s, K entrance 0.5 Kelbow-0.2, K exit ? 1. minor losses 9 Diameter = 0.5 ft. Elevation = 200 ft (1) KLentrance = 0.6 PUMP FORWEG -Total length of pipe = 200 ft Closed tank p = 3 psi Air (2) Elevation = 195 ft PPRONTPEERRING 1.55 ft 0.57 ft O 0.47 ft O

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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KLeibow= 0.3 In figure, if the velocity = 4 ft/s, K entrance= 0.5 Kelbow=0.2, K exit ?---==1, minor losses. Elevation = 200 ft Diameter = 0.5 ft. KLentrance = 0.6 PUMP TRESSINA CASSA Total length of pipe = 200 ft Closed tank- p = 3 psi Air (2) Elevation=195 ft 1.55 ft O 0.57 ft O 0.47 ft O
Transcribed Image Text:KLeibow= 0.3 In figure, if the velocity = 4 ft/s, K entrance= 0.5 Kelbow=0.2, K exit ?---==1, minor losses. Elevation = 200 ft Diameter = 0.5 ft. KLentrance = 0.6 PUMP TRESSINA CASSA Total length of pipe = 200 ft Closed tank- p = 3 psi Air (2) Elevation=195 ft 1.55 ft O 0.57 ft O 0.47 ft O
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