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kJ mol-1 e data at 373K to calculate the frequency factor, A. x 10 L mol 1s1 is the rate constant at 473 K? Enter your answer scientific notation: x 10 L mol-1s-1

kJ mol-1 e data at 373K to calculate the frequency factor, A. x 10 L mol 1s1 is the rate constant at 473 K? Enter your answer scientific notation: x 10 L mol-1s-1

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The decomposition of NOCl, \( 2\text{NOCl} \rightarrow 2\text{NO} + \text{Cl}_2 \), has \( k = 9.3 \times 10^{-5} \, \text{L mol}^{-1}\text{s}^{-1} \) at 100°C and \( k = 1.0 \times 10^{-3} \, \text{L mol}^{-1}\text{s}^{-1} \) at 130°C. (a) What is \( E_a \) for this reaction in kJ mol\(^{-1}\)? \[ E_a = \boxed{\phantom{00}} \, \text{kJ mol}^{-1} \] (b) Use the data at 373 K to calculate the frequency factor, \( A \). \[ A = \boxed{\phantom{00}} \times 10^{\boxed{\phantom{0}}} \, \text{L mol}^{-1}\text{s}^{-1} \] (c) What is the rate constant at 473 K? Enter your answer in scientific notation: \[ k = \boxed{\phantom{00}} \times 10^{\boxed{\phantom{0}}} \, \text{L mol}^{-1}\text{s}^{-1} \]
Transcribed Image Text:The decomposition of NOCl, \( 2\text{NOCl} \rightarrow 2\text{NO} + \text{Cl}_2 \), has \( k = 9.3 \times 10^{-5} \, \text{L mol}^{-1}\text{s}^{-1} \) at 100°C and \( k = 1.0 \times 10^{-3} \, \text{L mol}^{-1}\text{s}^{-1} \) at 130°C. (a) What is \( E_a \) for this reaction in kJ mol\(^{-1}\)? \[ E_a = \boxed{\phantom{00}} \, \text{kJ mol}^{-1} \] (b) Use the data at 373 K to calculate the frequency factor, \( A \). \[ A = \boxed{\phantom{00}} \times 10^{\boxed{\phantom{0}}} \, \text{L mol}^{-1}\text{s}^{-1} \] (c) What is the rate constant at 473 K? Enter your answer in scientific notation: \[ k = \boxed{\phantom{00}} \times 10^{\boxed{\phantom{0}}} \, \text{L mol}^{-1}\text{s}^{-1} \]
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