kg of salt A tank contains 60 kg of salt and 1000 L of water. Water containing 0.4 enters the tank at the rate 10. The solution is mixed and drains from the tank at the rate 2 min L .A(t) is the amount of salt in the tank at time t measured in kilograms. min (a) A(0) = 60 (kg) (b) A differential equation for the amount of salt in the tank is A'-4+2(A/(1000+8t)) t,A, A', A", for your variables, not A(t), and move everything to the left hand side.) (c) The integrating factor is (500+4t)^(1/4) (d) A(t)= (32t/5)(500+4t)^(5/4)(250t+t) (kg) = 0. (Use (e) Find the concentration of salt in the solution in the tank as time approaches infinity. (Assume your tank is large enough to hold all the solution.) concentration = kg L
kg of salt A tank contains 60 kg of salt and 1000 L of water. Water containing 0.4 enters the tank at the rate 10. The solution is mixed and drains from the tank at the rate 2 min L .A(t) is the amount of salt in the tank at time t measured in kilograms. min (a) A(0) = 60 (kg) (b) A differential equation for the amount of salt in the tank is A'-4+2(A/(1000+8t)) t,A, A', A", for your variables, not A(t), and move everything to the left hand side.) (c) The integrating factor is (500+4t)^(1/4) (d) A(t)= (32t/5)(500+4t)^(5/4)(250t+t) (kg) = 0. (Use (e) Find the concentration of salt in the solution in the tank as time approaches infinity. (Assume your tank is large enough to hold all the solution.) concentration = kg L
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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cant find questions D and E please help and show how you found it
Transcribed Image Text:kg
of salt
A tank contains 60 kg of salt and 1000 L of water. Water containing 0.4
enters the tank at the rate 10. The solution is mixed and drains from the tank at the rate 2
min
.A(t) is the amount of salt in the tank at time t measured in kilograms.
L
min
(a) A(0) = 60
(kg)
(b) A differential equation for the amount of salt in the tank is A'-4+2(A/(1000+8t))
t,A, A', A", for your variables, not A(t), and move everything to the left hand side.)
(c) The integrating factor is (500+4t)^(1/4)
(d) A(t)= (32t/5)(500+4t)^(5/4)(250t+t) (kg)
= 0. (Use
(e) Find the concentration of salt in the solution in the tank as time approaches infinity. (Assume
your tank is large enough to hold all the solution.)
concentration =
kg
L
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