The board of a major credit card company requires that the mean wait time for customers when they call customer service is at most 4.50 minutes. To make sure that themean wait time is not exceeding the requirement, an assistant manager tracks the wait times of 53 randomly selected calls. The mean wait time was calculated to be 4.94minutes. Assuming the population standard deviation is 2.10 minutes, is there sufficient evidence to say that the mean wait time for customers is longer than 4.50minutes with a 98 % level of confidence?Step 3 of 3: Draw a conclusion and interpret the decision.囲 TablesE KeypadAnswerKeyboard ShortcutsWe reject the null hypothesis and conclude that there is insufficient evidence at a 98 % level of confidence to support the claim that the mean wait time is longer than4.50 minutes.We fail to reject the null hypothesis and conclude that there is insufficient evidence at a 98 % level of confidence to support the claim that the mean wait time is longerthan 4.50 minutes.We reject the null hypothesis and conclude that there is sufficient evidence at a 98 % level of confidence to support the claim that the mean wait time is longer than4.50 minutes.We fail to reject the null hypothesis and conclude that there is sufficient evidence at a 98 % level of confidence to support the claim that the mean wait time is longerthan 4.50 minutes.Submit Answer© 2021 Hawkes Learning68°F Clearhere to searchSre schomedeleteTum&backsp Aceslock%23%247.3NE R T Yenter0)pausealtctrlUSE YOUR SMARTPHReviews VidensSpecs-Sun

Given : sample size, n = 53 sample mean, x̄ = 4.94 population standard…

Answered: Keyboard Shortcuts We reject the null…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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