2.0 m KEY CONCEPT FIGURE 16.13 Possible standing-wave modes of a string fixed at both ends. m=1 m=2 m= 3 L L The mode number is equal to the number of antinodes. d1 = 4 = 21. h=L) A3 =4 = 3L f= 3(I.)
2.0 m KEY CONCEPT FIGURE 16.13 Possible standing-wave modes of a string fixed at both ends. m=1 m=2 m= 3 L L The mode number is equal to the number of antinodes. d1 = 4 = 21. h=L) A3 =4 = 3L f= 3(I.)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 2.0-m-long string carries a standing wave as in the figure at right. Extend the pattern and the formulas as shown to determine the mode number and the wavelength of this particular standing-wave mode.
A. m = 6, λ = 0.67 m B. m = 6, λ = 0.80 m C. m = 5, λ = 0.80 m
D. m = 5, λ = 1.0 m E. m = 4, λ = 0.80 m F. m = 4, λ = 1.0 m
![2.0 m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb8ffcafa-837a-4ee7-8dde-d6f3309acbf2%2F0369b27f-37ad-451a-8c79-294ffa0b9ac1%2F07d5z3l.png&w=3840&q=75)
Transcribed Image Text:2.0 m
![KEY CONCEPT
FIGURE 16.13 Possible standing-wave modes of a string fixed at both ends.
m=1
m=2
m= 3
L
L
The mode
number is
equal to the
number of
antinodes.
d1 = 4 = 21. h=L)
A3 =4 = 3L f= 3(I.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb8ffcafa-837a-4ee7-8dde-d6f3309acbf2%2F0369b27f-37ad-451a-8c79-294ffa0b9ac1%2Fq0dsk4a.png&w=3840&q=75)
Transcribed Image Text:KEY CONCEPT
FIGURE 16.13 Possible standing-wave modes of a string fixed at both ends.
m=1
m=2
m= 3
L
L
The mode
number is
equal to the
number of
antinodes.
d1 = 4 = 21. h=L)
A3 =4 = 3L f= 3(I.)
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