kercises. Solving a Polynomial Equation In A Exercises 29-32, find all real solutions of the polynomial equation. 2.5 Zeros of Polynomial Factoring a Polynomial In Es the polynomial (a) as the produe irreducible over the rationals, (b) s and quadratic factors that are irn and (c) in completely factored fo (29.-5x3 + 11x- 4x - 2 0 30. 8x + 10x² – 15x – 6 = 0 31. x4 + 6x³ + 3x² – 16x + 6 = 0 32. x4 + 8x³ + 14x² - 17x – 42 = 0 leing the Rational Zero Test In Exercises 33–36, a list the possible rational zeros of f, (b) sketch the 51. f(x) = x* + 2-8 52. f(x) = x* + 6x-27 53. f(x) = x*- 2x-3x + (Hint: One factor is x graph of f so that some of the possible zeros in part (a) can be disregarded, and then (c) determine all real 54. f(x) = x - 3x-x² %3D (Hint: One factor is x zeros of f. Finding th Function 33. f(x) = x³ + x² – 4x – 4 34. f(x) = - 3x³ + 20x² – 36x + 16 zero to fin Function 35. f(x) = -4x + 15x2 – 8x - 3 %3D 55. f(x) = x³ – x² 36. f(x) = 4xr³ – 12x2 - x + 15 %3D 56. f(x) = 2x + %3D A Using the Rational Zero Test In Exercises 37–40, (a) list the possible rational zeros of f, (b) use a graphing 57. g(x) = x³ – 58. g(x) = x³ + %3D part (a) can be disregarded, and then (c) determine all real zeros of f. utility to graph f so that some of the possible zeros in 59. h(x) = x* 60. h(x) = xª
kercises. Solving a Polynomial Equation In A Exercises 29-32, find all real solutions of the polynomial equation. 2.5 Zeros of Polynomial Factoring a Polynomial In Es the polynomial (a) as the produe irreducible over the rationals, (b) s and quadratic factors that are irn and (c) in completely factored fo (29.-5x3 + 11x- 4x - 2 0 30. 8x + 10x² – 15x – 6 = 0 31. x4 + 6x³ + 3x² – 16x + 6 = 0 32. x4 + 8x³ + 14x² - 17x – 42 = 0 leing the Rational Zero Test In Exercises 33–36, a list the possible rational zeros of f, (b) sketch the 51. f(x) = x* + 2-8 52. f(x) = x* + 6x-27 53. f(x) = x*- 2x-3x + (Hint: One factor is x graph of f so that some of the possible zeros in part (a) can be disregarded, and then (c) determine all real 54. f(x) = x - 3x-x² %3D (Hint: One factor is x zeros of f. Finding th Function 33. f(x) = x³ + x² – 4x – 4 34. f(x) = - 3x³ + 20x² – 36x + 16 zero to fin Function 35. f(x) = -4x + 15x2 – 8x - 3 %3D 55. f(x) = x³ – x² 36. f(x) = 4xr³ – 12x2 - x + 15 %3D 56. f(x) = 2x + %3D A Using the Rational Zero Test In Exercises 37–40, (a) list the possible rational zeros of f, (b) use a graphing 57. g(x) = x³ – 58. g(x) = x³ + %3D part (a) can be disregarded, and then (c) determine all real zeros of f. utility to graph f so that some of the possible zeros in 59. h(x) = x* 60. h(x) = xª
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
How do you answer 33? In addition, in terms of part B (although, I would like each part answered), how do you "disregard" some of the possible zeros from part (a)? Shouldn't you answer part C to be able to disregard said possible zeros and thus graph it accurately?
![kercises.
Solving a Polynomial Equation In
A
Exercises 29-32, find all real solutions of the
polynomial equation.
2.5
Zeros of Polynomial
Factoring a Polynomial In Es
the polynomial (a) as the produe
irreducible over the rationals, (b) s
and quadratic factors that are irn
and (c) in completely factored fo
(29.-5x3 + 11x- 4x - 2 0
30. 8x + 10x² – 15x – 6 = 0
31. x4 + 6x³ + 3x² – 16x + 6 = 0
32. x4 + 8x³ + 14x² - 17x – 42 = 0
leing the Rational Zero Test In Exercises 33–36,
a list the possible rational zeros of f, (b) sketch the
51. f(x) = x* + 2-8
52. f(x) = x* + 6x-27
53. f(x) = x*- 2x-3x +
(Hint: One factor is x
graph of f so that some of the possible zeros in part (a)
can be disregarded, and then (c) determine all real
54. f(x) = x - 3x-x²
%3D
(Hint: One factor is x
zeros of f.
Finding th
Function
33. f(x) = x³ + x² – 4x – 4
34. f(x) = - 3x³ + 20x² – 36x + 16
zero to fin
Function
35. f(x) = -4x + 15x2 – 8x - 3
%3D
55. f(x) = x³ – x²
36. f(x) = 4xr³ – 12x2 - x + 15
%3D
56. f(x) = 2x +
%3D
A Using the Rational Zero Test In Exercises 37–40,
(a) list the possible rational zeros of f, (b) use a graphing
57. g(x) = x³ –
58. g(x) = x³ +
%3D
part (a) can be disregarded, and then (c) determine all
real zeros of f.
utility to graph f so that some of the possible zeros in
59. h(x) = x*
60. h(x) = xª](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5626993-b727-4c20-ac41-598acbf5e92b%2Fa39d08f0-af6b-45d4-afe6-372e231d333f%2Fzw8mnke.jpeg&w=3840&q=75)
Transcribed Image Text:kercises.
Solving a Polynomial Equation In
A
Exercises 29-32, find all real solutions of the
polynomial equation.
2.5
Zeros of Polynomial
Factoring a Polynomial In Es
the polynomial (a) as the produe
irreducible over the rationals, (b) s
and quadratic factors that are irn
and (c) in completely factored fo
(29.-5x3 + 11x- 4x - 2 0
30. 8x + 10x² – 15x – 6 = 0
31. x4 + 6x³ + 3x² – 16x + 6 = 0
32. x4 + 8x³ + 14x² - 17x – 42 = 0
leing the Rational Zero Test In Exercises 33–36,
a list the possible rational zeros of f, (b) sketch the
51. f(x) = x* + 2-8
52. f(x) = x* + 6x-27
53. f(x) = x*- 2x-3x +
(Hint: One factor is x
graph of f so that some of the possible zeros in part (a)
can be disregarded, and then (c) determine all real
54. f(x) = x - 3x-x²
%3D
(Hint: One factor is x
zeros of f.
Finding th
Function
33. f(x) = x³ + x² – 4x – 4
34. f(x) = - 3x³ + 20x² – 36x + 16
zero to fin
Function
35. f(x) = -4x + 15x2 – 8x - 3
%3D
55. f(x) = x³ – x²
36. f(x) = 4xr³ – 12x2 - x + 15
%3D
56. f(x) = 2x +
%3D
A Using the Rational Zero Test In Exercises 37–40,
(a) list the possible rational zeros of f, (b) use a graphing
57. g(x) = x³ –
58. g(x) = x³ +
%3D
part (a) can be disregarded, and then (c) determine all
real zeros of f.
utility to graph f so that some of the possible zeros in
59. h(x) = x*
60. h(x) = xª
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