Katie thinks that people living in a rural environment have a healthier lifestyle than other people. She believes the average lifespan in the USA is77 years and the lifespans follow an approximately normal distribution. A random sample of 14 obituaries from newspapers from rural towns inIdaho give 79.69 and s = 0.99. Does this sample provide evidence that people living in rural Idaho communities live longer than 77 years?=(a) State the null and alternative hypotheses: (Type "mu" for the symbol μ, e.g. mu >1 for the mean is greater than 1, mu <1 for the mean isless than 1, mu not = 1 for the mean is not equal to 1)Ho: 77Ha: 77(b) Find the test statistic = 10.16705(c) Answer the question: Does this sample provide evidence that people living in rural Idaho communities live longer than 77 years? (Use a 10%level of significance)(Type: Yes or No) yes

(a). Ho (Null Hypothesis): The average lifespan of people living in rural Idaho communities is the…

Answered: Katie thinks that people living in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

Two samples. each with n = 5 scores, have a pooled variance of 40. What is the estimated standard error for the sample mean uniference? how do i solve?
Suppose that a random sample of 11 scores from a population of test scores is to be used to estimate the population mean and standard deviation. If a 95% confidence interval for the mean is constructed , it contains values that are within _____ standard deviations of its mean.
In a hypothesis test, if the null hypothesis states that the population mean is equal to 100 with a standard deviation of 15, and the sample mean is 108 with a sample size of 36, what is the calculated z-score for this test?
Part b and c
A newsletter publisher believes that less than 36%36% of their readers own a laptop. For marketing purposes, a potential advertiser wants to confirm this claim. After performing a test at the 0.010.01 level of significance, the advertiser failed to reject the null hypothesis. What is the conclusion regarding the publisher's claim?
Suppose the national average dollar amount for an automobile insurance claim is $670.543. You work for an agency in Michigan and you are interested in whether or not the state average is different from the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ = 670.543, Alternative Hypothesis: μ ≠ 670.543. A random sample of 27 claims shows an average amount of $668.645 with a standard deviation of $68.6867. What is the test statistic and p-value for this test? Question 8 options: 1) Test Statistic: -0.144, P-Value: 0.44345 2) Test Statistic: -0.144, P-Value: 0.5566 3) Test Statistic: -0.144, P-Value: 1.5566 4) Test Statistic: 0.144, P-Value: 0.8869 5) Test Statistic: -0.144, P-Value: 0.8869
The College Board reports that the scores on the math SAT were normally distributed with a mean of 525. A random sample of 15 students at your high school had a mean of 550 and a sample standard deviation of 105. What values of the sample mean would lead to rejection of the null hypothesis at the 0.01 level of significance?
2) A restaurant association claims that the average amount a family spends per year eating out is $2700. Suppose you are a consumer reporter and want to test this claim. You select a random sample of 32 homes and obtain that their mean is $2850 with a standard deviation of $270. using α= 0.05, do you have enough evidence to reject the association's claim?
Answer the following True or False: Suppose a hypothesis test was performed with a level of significance of 0.05. Then if the null hypothesis is actually true, then there is a 5% chance that the researcher will end up accepting the alternative hypothesis in error. false true
In 1995, it was determined that 78% of US citizens supported a ban on household aerosols. Thinking that this proportion may have changed over the past few decades, a sample will be taken to test if a change has occurred. In a SRS of 500 citizens taken this year, 350 supported the ban. Determine the pvalue associated with the test. find null and alternate hypothesis.
Question 2: A random sample of 200 observations produced a sample proportion of 0.35. Determine the 98% confidence interval for the population proportion. rt Answer:
Suppose a sample of 9 customers spends an average of $200 with a standard deviation $20 what is a 95% confidence interval for the sample mean. Use the fact that 95% of sample means are within 2.306 standard errors of the sample mean.

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