Katie thinks that people living in a rural environment have a healthier lifestyle than other people. She believes the average lifespan in the USA is77 years and the lifespans follow an approximately normal distribution. A random sample of 14 obituaries from newspapers from rural towns inIdaho give 79.69 and s = 0.99. Does this sample provide evidence that people living in rural Idaho communities live longer than 77 years?=(a) State the null and alternative hypotheses: (Type "mu" for the symbol μ, e.g. mu >1 for the mean is greater than 1, mu <1 for the mean isless than 1, mu not = 1 for the mean is not equal to 1)Ho: 77Ha: 77(b) Find the test statistic = 10.16705(c) Answer the question: Does this sample provide evidence that people living in rural Idaho communities live longer than 77 years? (Use a 10%level of significance)(Type: Yes or No) yes

(a). Ho (Null Hypothesis): The average lifespan of people living in rural Idaho communities is the…

Answered: Katie thinks that people living in a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

In a hypothesis test, if the null hypothesis states that the population mean is equal to 100 with a standard deviation of 15, and the sample mean is 108 with a sample size of 36, what is the calculated z-score for this test?
A news article that you read stated that 58% of voters prefer the Democratic candidate. You think that the actual percent is smaller. 150 of the 300 voters that you surveyed said that they prefer the Democratic candidate. What can be concluded at the 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) Ha: (Please enter a decimal) The test statistic = (please show your answer to 4 decimal places.) The p-value = (please show your answer to 4 decimal places)
A 95% confidence interval for the mean body mass index (BMI) of young American women is 26.8±0.626.8±0.6. One of your classmates interprets this interval in the following way: “The mean BMI of young American women cannot be 28.” Is your classmate’s interpretation correct? If not, what is the correct interpretation of the confidence interval? Incorrect. We are 95% confident that future samples of young women will have mean BMI between 26.2 and 27.4. Incorrect. We are 95% confident that the interval from 26.2 and 27.4 captures the BMI of all young American women. Correct. The interval states that the mean BMI of young American women is between 26.2 and 27.4, so the mean cannot be 28. Incorrect. We are 95% confident that the interval from 26.2 and 27.4 captures the true mean BMI of all young American women. Incorrect. If we take many samples, the population mean BMI will be between 26.2 and 27.4 in about 95% of those samples.
Suppose the national average dollar amount for an automobile insurance claim is $670.543. You work for an agency in Michigan and you are interested in whether or not the state average is different from the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ = 670.543, Alternative Hypothesis: μ ≠ 670.543. A random sample of 27 claims shows an average amount of $668.645 with a standard deviation of $68.6867. What is the test statistic and p-value for this test? Question 8 options: 1) Test Statistic: -0.144, P-Value: 0.44345 2) Test Statistic: -0.144, P-Value: 0.5566 3) Test Statistic: -0.144, P-Value: 1.5566 4) Test Statistic: 0.144, P-Value: 0.8869 5) Test Statistic: -0.144, P-Value: 0.8869
The College Board reports that the scores on the math SAT were normally distributed with a mean of 525. A random sample of 15 students at your high school had a mean of 550 and a sample standard deviation of 105. What values of the sample mean would lead to rejection of the null hypothesis at the 0.01 level of significance?
2) A restaurant association claims that the average amount a family spends per year eating out is $2700. Suppose you are a consumer reporter and want to test this claim. You select a random sample of 32 homes and obtain that their mean is $2850 with a standard deviation of $270. using α= 0.05, do you have enough evidence to reject the association's claim?
Answer the following True or False: Suppose a hypothesis test was performed with a level of significance of 0.05. Then if the null hypothesis is actually true, then there is a 5% chance that the researcher will end up accepting the alternative hypothesis in error. false true
When Mendel conducted his famous genetics experiments with peas, one sample of offspring consisted of 428 green peas and 152 yellow peas. 3. a. Find a 99% confidence interval estimate of the percentage of yellow peas.
In 1995, it was determined that 78% of US citizens supported a ban on household aerosols. Thinking that this proportion may have changed over the past few decades, a sample will be taken to test if a change has occurred. In a SRS of 500 citizens taken this year, 350 supported the ban. Determine the pvalue associated with the test. find null and alternate hypothesis.
Question 2: A random sample of 200 observations produced a sample proportion of 0.35. Determine the 98% confidence interval for the population proportion. rt Answer:
Suppose a sample of 9 customers spends an average of $200 with a standard deviation $20 what is a 95% confidence interval for the sample mean. Use the fact that 95% of sample means are within 2.306 standard errors of the sample mean.

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