Karen wants to advertise how many chocolate chips are in each Big Chip cookie at her bakery. Sherandomly selects a sample of 72 cookies and finds that the number of chocolate chips per cookie inthe sample has a mean of 15.6 and a standard deviation of 2.8.What is the 99% confidence interval for the number of chocolate chips per cookie for Big Chipcookies?Round your answer to 2 decimal places.<με

Answered: Image /qna-images/answer/143ee604-df06-4e20-b80e-3bafa309ef32.jpg

Answered: Karen wants to advertise how many…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
A sumple from a normal population with mu = 50 and sigma = 6 of M=48.20, . the sample mean.corresponds to tz = - 1.50 , then how many scores are in the sample?
In a sample of 12 randomly selected high school seniors, the mean score on a standardized test was 1182 and the standard deviation was 161.6.Further research suggests that the population mean score on this test for high school seniors is 1012. Does the t-value for the original sample fall between −t0.95 and t0.95? Assume that the population of test scores for high school seniors is normally distributed. What is The t-value? And does or does not it not fall between −t0.95 and t0.95 because t0.95=? (Round to two decimal places as needed.)
Erin is a nutritionist and cardiologist. She is testing whether the average total cholesterol level of adults in the region is less than 175mgdL. Erin randomly selects 25 people in the region who willingly allowed their blood to be drawn for the survey. Based on several previous studies, Erin assumes that the population standard deviation for the total cholesterol level is 30.22mgdL. For this test: H0:μ=175; Ha:μ<175, which is a left-tailed test. The test results are: z0=−1.158, p-value is = 0.123 Using a 5% level of significance, which of the following are appropriate conclusions for this hypothesis test? Select all that apply. Select all that apply: We reject H0. We fail to reject H0. At the 5% significance level, the data provide sufficient evidence to conclude that the average total cholesterol level of adults in the region is less than 175mgdL. At the 5% significance level, the data do not provide sufficient evidence to conclude that…
Mike thinks that there is a difference in quality of life between rural and urban living. He collects information from
Assume that the mean height of men in the United States is 70 inches, with a standard deviation of 3 inches. A particular man is 80 inches tall. Find the z-score of his height. (Round to two decimal places.)
Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40 individuals. The average time that the 40 people spent reading the paper was 12.4 minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the mean. (a) State the hypothesis and identify the claim with the correct hypothesis. :H0 ▼(Choose one) :H1 ▼(Choose one) This hypothesis test is a ▼(Choose one) test. (b)Find the critical value(s). Round the answer to 2 decimal places, if necessary. Critical values: (c)Compute the test value. Round the answer to at least 2 decimal places, if necessary. z= (d)Make the decision.…
A manufacturer of light bulbs finds that one light bulb model has a mean life span of 1025 h with a standard deviation of 83 h.Find the z-scores for lightbulbs which last 850 and 900 h. (Round your answers to two decimal places.) 850 h: z = 900 h: z =
A manufacturer of light bulbs finds that one light bulb model has a mean life span of 1024 h with a standard deviation of 82 h.Find the z-scores for lightbulbs which last 810 and 890 h. (Round your answers to two decimal places.) 810 h: z = 890 h: z =
A distribution of values is normal with a mean of 100.9 and a standard deviation of 60.6.Find P72, which is the score separating the bottom 72% from the top 28%.
Newspaper Reading Times A survey taken several years ago found that the average time a person spent reading the local daily newspaper was 10.8 minutes. The standard deviation of the population was 3 minutes. To see whether the average time had changed since the newspaper's format was revised, the newspaper editor surveyed 40 individuals. The average time that the 40 people spent reading the paper was 12.4 minutes. At α=0.10 , is there a change in the average time an individual spends reading the newspaper? Find the 90% confidence interval of the mean. **NOTE** I already have answer for a,b, and c (d)Make the decision. ▼(Choose one) the null hypothesis. (e)Summarize the results. There ▼(Choose one) enough evidence to support the claim that there is a change in the average time an individual spends reading the newspaper. Find the 90% confidence interval of the mean. Round the answers to nearest whole number. <u< (f)Do the results agree?…

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