(k+1)! −1+ (k+1) ( K+1)! (k+1)! [₁ + (k+1)] = = (k+1)! (k+²) -1 (k+2)! - 1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Can you please explain how line 1 became line 2 and so on I am confused on the algerba.
![= (k+1)! −1 + (K+1) (k+1)!
(k+1)! [ 1 + (k+1)] -1
=
= (k+1)! (k+²) -1
= (k+2)! ~1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F14bb29d5-3c37-4885-9c88-f4870b6f7d8f%2F205a0d19-c047-46b2-80e9-9da75467e410%2Fkc9tw9i_processed.png&w=3840&q=75)
Transcribed Image Text:= (k+1)! −1 + (K+1) (k+1)!
(k+1)! [ 1 + (k+1)] -1
=
= (k+1)! (k+²) -1
= (k+2)! ~1
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Follow-up Question
please explain to me why the first line gives (1+ k + 1) I have been stuck on this for a long time :( Thank you.

Transcribed Image Text:(k+ 1)! + (k+ 1)(k + 1)! − 1
||
=
(k+ 1)!(1+k+1)-1
Solution
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