[K] = {xez/x = k moon] we for these equivalence classes ve define addition as follows: [a] + [b] = [a+b] Example Z3 Z₂ = { [0], [₁], [²]} 3 [0] = {..., −6,-3, 0, 6, 9,... } [1] = {ace, -5, -2, 1, 4, 7, .... Y [2] = {..., -4₁ -1, 2, 5, 8,...3
[K] = {xez/x = k moon] we for these equivalence classes ve define addition as follows: [a] + [b] = [a+b] Example Z3 Z₂ = { [0], [₁], [²]} 3 [0] = {..., −6,-3, 0, 6, 9,... } [1] = {ace, -5, -2, 1, 4, 7, .... Y [2] = {..., -4₁ -1, 2, 5, 8,...3
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I don't understand why [0] equals that. Same for [1] and [2]
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