K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. (d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.? (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 6 or fewer customers waiting for a table at 6:00 P.M.? O A. (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. Frequency 2012 4 7 10 13 16 Number of Customers B. Frequency 6 7 5 9 10 8 11 10 11 10 6 13 13 12 7 11 8 3 BENDRO LLL 4 7 10 13 16 Number of Customers Frequency 9 7 3 7 7 8 7 9 7 9 4 7 8529636 4 7 10 13 16 Number of Customers Frequency D. 8529630 6 5 10 8 9 9 12 8 11 50 E L 4 7 10 13 16 Number of Customers
K The data to the right represent the number of customers waiting for a table at 6:00 P.M. for 40 consecutive Saturdays at Bobak's Restaurant. Complete parts (a) through (h) below. (d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.? (Type an integer or a decimal. Do not round.) (e) What percentage of the Saturdays had 6 or fewer customers waiting for a table at 6:00 P.M.? O A. (Type an integer or a decimal. Do not round.) (f) Construct a frequency histogram of the data. Choose the correct histogram below. Frequency 2012 4 7 10 13 16 Number of Customers B. Frequency 6 7 5 9 10 8 11 10 11 10 6 13 13 12 7 11 8 3 BENDRO LLL 4 7 10 13 16 Number of Customers Frequency 9 7 3 7 7 8 7 9 7 9 4 7 8529636 4 7 10 13 16 Number of Customers Frequency D. 8529630 6 5 10 8 9 9 12 8 11 50 E L 4 7 10 13 16 Number of Customers
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![1:55
K
The data to the right represent the number of
customers waiting for a table at 6:00 P.M. for 40
consecutive Saturdays at Bobak's Restaurant.
Complete parts (a) through (h) below.
Frequency
(d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.?
%
(Type an integer or a decimal. Do not round.)
(f) Construct a frequency histogram of the data. Choose the correct histogram below.
A.
(Type an integer or a decimal. Do not round.)
(e) What percentage of the Saturdays had 6 or fewer customers waiting for a table at 6:00 P.M.?
O A.
Relative Frequency
4 7 10 13 16
Number of Customers
0.64
0.5-
0.4
0.34
0.3
1
0.1-
0-
14 7 10 13 16
Number of Customers
B.
L
1 4 7 10 13 16
Number of Customers
(g) Construct a relative frequency histogram of the data. Choose the correct histogram below.
|||
Frequency
=
8529630
O B.
Relative Frequency
4 7 10 13 16
Number of Customers
0.6-
0.5-
0.4-
0.2-
0.1-
0-
1 4 7 10 13 16
Number of Customers
Q
10
11
11
13
7
Frequency
O
C.
Relative Frequency
1852963c
O C.
2 | 46 | - 21%
LTE2
8
6
7
10 5
9
10 6
3
13 12
7
11 8 9
0.6-
0.5-
0.4-
0.3-
0.2-
0-
(h) Describe the shape of the distribution. Choose the correct answer below.
9 7 6
7 5
8
8
7 9
4 7 10 13 16
Number of Customers
3
7
9
4 7 11
Q
Frequency
O D.
Relative Frequency
daddy
0.6-
0.5-
0.4-
0.3-
0.2-
0.1-
0-
50
10
12
L
1 4 7 10 13 16
Number of Customers.
O A. The distribution is symmetric because the bars in the histograms are all approximately the same height.
B. The distribution is symmetric because the left and right sides are approximately mirror images.
OC. The distribution is skewed right because the right tail is longer than the left tail.
O D. The distribution is skewed left because the left tail is longer than the right tail.
O E. The distribution is skewed left because the right tail is longer than the left tail.
O F. The distribution is skewed right because the left tail is longer than the right tail.
1 4 7 10 13 16
Number of Customers](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50f06152-6ab7-40cf-844d-29583a7c45f7%2F8c478b39-4eb5-49db-8115-a6c3d7e58eeb%2Fpz33ckb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1:55
K
The data to the right represent the number of
customers waiting for a table at 6:00 P.M. for 40
consecutive Saturdays at Bobak's Restaurant.
Complete parts (a) through (h) below.
Frequency
(d) What percentage of the Saturdays had 4 or more customers waiting for a table at 6:00 P.M.?
%
(Type an integer or a decimal. Do not round.)
(f) Construct a frequency histogram of the data. Choose the correct histogram below.
A.
(Type an integer or a decimal. Do not round.)
(e) What percentage of the Saturdays had 6 or fewer customers waiting for a table at 6:00 P.M.?
O A.
Relative Frequency
4 7 10 13 16
Number of Customers
0.64
0.5-
0.4
0.34
0.3
1
0.1-
0-
14 7 10 13 16
Number of Customers
B.
L
1 4 7 10 13 16
Number of Customers
(g) Construct a relative frequency histogram of the data. Choose the correct histogram below.
|||
Frequency
=
8529630
O B.
Relative Frequency
4 7 10 13 16
Number of Customers
0.6-
0.5-
0.4-
0.2-
0.1-
0-
1 4 7 10 13 16
Number of Customers
Q
10
11
11
13
7
Frequency
O
C.
Relative Frequency
1852963c
O C.
2 | 46 | - 21%
LTE2
8
6
7
10 5
9
10 6
3
13 12
7
11 8 9
0.6-
0.5-
0.4-
0.3-
0.2-
0-
(h) Describe the shape of the distribution. Choose the correct answer below.
9 7 6
7 5
8
8
7 9
4 7 10 13 16
Number of Customers
3
7
9
4 7 11
Q
Frequency
O D.
Relative Frequency
daddy
0.6-
0.5-
0.4-
0.3-
0.2-
0.1-
0-
50
10
12
L
1 4 7 10 13 16
Number of Customers.
O A. The distribution is symmetric because the bars in the histograms are all approximately the same height.
B. The distribution is symmetric because the left and right sides are approximately mirror images.
OC. The distribution is skewed right because the right tail is longer than the left tail.
O D. The distribution is skewed left because the left tail is longer than the right tail.
O E. The distribution is skewed left because the right tail is longer than the left tail.
O F. The distribution is skewed right because the left tail is longer than the right tail.
1 4 7 10 13 16
Number of Customers
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