k т h(k + €) = () ) h(k +l) k+l h(k + l) h1(k + l). || ||

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Another way to derive this same result is to start with
Ck
B,
Ck-1
or Ck = Aß,
(8.20)
in equation (8.9). Substituting this function in equation (8.9) and simplifying
gives
qDe+1 – BDe + (pß²)De-1 = 0,
(8.21)
which has the characteristic equation
qr2 – Br + pg? = 0.
(8.22)
Therefore,
ri = B,
PB
r2 =
(8.23)
and
De = A3(B)B + A4(B)
(8.24)
Since z(k, l, B) = CkDe, we have
z(k, l, 3) = Ā3(3),3* +€+ Ā4(18) () 3*ie,
(8.25)
where [A3(B), A4(B), A3 (B), A4(3)] are arbitrary functions of B. If we now
sum/integrate over ß, then
z(k, l) = g1(k + l) +
h1(k + l),
(8.26)
and h1 are functions of (k +l).
Let's now show that equations (8.19) and (8.26) are the same. To do this,
where
9i
define a new discrete variable
m = k + l.
(8.27)
Therefore,
k
m-l
(:)" (;)
(8.28)
and
k
m
h(k +l) =
h(k + l)
k+l
h(k +l)
h1(k + l).
(8.29)
This shows that equations (8.19) and (8.26) are equal.
Transcribed Image Text:Another way to derive this same result is to start with Ck B, Ck-1 or Ck = Aß, (8.20) in equation (8.9). Substituting this function in equation (8.9) and simplifying gives qDe+1 – BDe + (pß²)De-1 = 0, (8.21) which has the characteristic equation qr2 – Br + pg? = 0. (8.22) Therefore, ri = B, PB r2 = (8.23) and De = A3(B)B + A4(B) (8.24) Since z(k, l, B) = CkDe, we have z(k, l, 3) = Ā3(3),3* +€+ Ā4(18) () 3*ie, (8.25) where [A3(B), A4(B), A3 (B), A4(3)] are arbitrary functions of B. If we now sum/integrate over ß, then z(k, l) = g1(k + l) + h1(k + l), (8.26) and h1 are functions of (k +l). Let's now show that equations (8.19) and (8.26) are the same. To do this, where 9i define a new discrete variable m = k + l. (8.27) Therefore, k m-l (:)" (;) (8.28) and k m h(k +l) = h(k + l) k+l h(k +l) h1(k + l). (8.29) This shows that equations (8.19) and (8.26) are equal.
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