1:21K(a) % (Type an integer or a decimal.)Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 18. Use theempirical rule to determine the following.(a) What percentage of people has an IQ score between 82 and 118?(b) What percentage of people has an IQ score less than 82 or greater than 118?(c) What percentage of people has an IQ score greater than 136?|||=LTE 2.1 4GO52%

Answered: K Scores of an IQ test have a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Could you please highlight the correct answer. and explain it
3
Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 171 adult males, the mean pulse rate is 68.2 bpm and the standard deviation is 10.91 bpm. Find the value of the test statistic.
12
Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 136 adult males, the mean pulse rate is 69.6 bpm and the standard deviation is 11.4 bpm. Find the value of the test statistic.
The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
Calculate : (i) Quartile deviation (Q.D.), and (ii) Mean Deviation (M.D.) from mean, f the following data : Marks. : No. of Students : 3. 0-10 6 10-20 5 20-30 30-40 40-50 15 50-60 60-70 3
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
9 The weights for a group of 18-month-old girls are normally distributed with a mean of 24.7pounds and a standard deviation of 2.2 pounds. Use the given table to find the percentage of 18-month-old girls who weigh between 22.2 and 23.1 pounds. z-score -3.0 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -2.2 -2.1 Percentile 0.13 0.19 0.26 0.35 0.47 0.62 0.82 1.07 1.39 1.79 z-score -2.0 -1.9 -1.8 -1.7 -1.6 -1.5 -1.4 -1.3 -1.2 -1.1 Percentile 2.28 2.87 3.59 4.46 5.48 6.68 8.08 9.68 11.51 13.57 z-score -1.0 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2 -0.1 Percentile 15.87 18.41 21.19 24.20 27.43 30.85 34.46 38.21 42.07 46.02 ________% of 18-month-old girls weigh between 22.2 and 23.1 pounds. (Round the final answer to the nearest hundredth as needed. Round the z-score to the nearest tenth as needed.)
You are testing the claim that the mean GPA of night students is different than the mean GPA of day students.You sample 25 night students, and the sample mean GPA is 2.57 with a standard deviation of 0.83You sample 45 day students, and the sample mean GPA is 2.12 with a standard deviation of 0.49Calculate the test statistic, rounded to 2 decimal places
Claim: The standard deviation of pulse rates of adult males is more than 12 bpm. For a random sample of 172 adult males, the pulse rates have a standard deviation of 11.5 bpm. Find the value of the test statistic?
Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 28 and the age of the winner for best actress was 44. For all best actors, the mean age is 42.3 years and the standard deviation is 8.4 years. For all best actresses, the mean age is 33.3 years and the standard deviation is 10.7 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z = and the z score for the actress is z=, the had the more extreme age. (Round to two decimal places.)

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